Answer:
sqrt(area)
Explanation:
- Here sqrt is a short form of square root.
- area is a variable name having he area of square.
- When the function is called, it will give the square root of the value stored in variable area.
As we have to find the length of the diagonal, we must knew that as all sides of the square are same in length so are the diagonals. This means that each of the four sides of the square and it diagonals are equal in length.
So a square has: length=breadth=diagonal
As Area= length*breadth
√area = length (as length = diagonal length)
So √area = diagonal length
Answer:
Code is given below and output is attached as an image.
Explanation:
#include <iostream>
#include <fstream>
using namespace std;
bool isPalindrome(int n)
{
// Find reverse of n
int rev = 0;
for (int i = n; i > 0; i /= 10)
rev = rev * 10 + i % 10;
// If n and rev are same,then n is a palindrome
return (n == rev);
}
int main()
{
int min = 1; // Lower Bound
int max = 200; // Upper Bound
ofstream myfile;
myfile.open("palindrome.txt");
for (int i = min + 1; i < max; i++)
if (isPalindrome(i))
myfile << i << endl;
myfile.close();
return 0;
}
In python 3.8:
user_input = input().split()
x = user_input[0]
char = user_input[-1]
for w in range(1,int(x)+1):
if char in user_input[w]:
print(user_input[w])
I hope this helps
Answer:
Explanation:
The following code is written in Java. It is a method that calculates the square root of a number as requested. The method first checks with an IF statement if the parameter value is a positive number and then calculates the square root and prints it to the screen. Otherwise, it prints Number must not be negative. A test case has been provided in the main method and the output can be seen in the attached image below.
import java.util.Scanner;
class Brainly {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a number of type double to calculate square root:");
double num = in.nextDouble();
rootPositive(num);
}
public static void rootPositive(double num) {
if (num > 0) {
System.out.println(Math.sqrt(num));
} else {
System.out.println("Number must not be negative.");
}
}
}
Answer:
All of the above
Explanation:
An interrupt priority scheme is a system which decides the priority at which various work is done and it perform all of the above mention task so therefore all of the above is the right answer.