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Crank
3 years ago
6

In which quadrant does the point (-5, -21) lie? A. Quadrant IV B. Quadrant I C. Quadrant III D. Quadrant II

Mathematics
2 answers:
Klio2033 [76]3 years ago
7 0

Answer:

Quadrant 3

Step-by-step explanation:

Vilka [71]3 years ago
6 0

Answer:

Quadrant 3

Step-by-step explanation:

All negatives all fall under 3

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Which of the following congruency statements is correct? Yzx = bcd, yzx = dcb, zxy =dcb, yxz = cdb
goldenfox [79]

Answer:c

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Graph the system &amp; write its solution <br> 2x+y=-4<br> Y=-1/2x-1
xz_007 [3.2K]

Answer:

The solution of system of equation is (-2,0)

Step-by-step explanation:

Given system of equation are

Equation 1 :      2x+y=(-4)

Equation 2 :      y+\frac{1}{2}x=(-1)

To plot the equation of line, we need at least two points

For Equation 1 : 2x+y=(-4)

Let x=0

2x+y=(-4)

2(0)+y=(-4)

y=(-4)

Let x=1

2x+y=(-4)

2(1)+y=(-4)

y=(-6)

Therefore,

The required points for equation is (0,-4) and (1,-6)

For Equation 2 : y+\frac{1}{2}x=(-1)

Let x=0

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(0)=(-1)

y=(-1)

Let x=2

y+\frac{1}{2}x=(-1)

y+\frac{1}{2}(2)=(-1)

y=(-2)

The required points for equation is (0,-1) and (2,-2)

Now, plot the graph using this points

From the graph,

The red line is equation 1 and blue line is equation 2

Since. The point of intersection is solution of system of equations

The solution of system of equation is (-2,0)

6 0
3 years ago
Fond the equation of the line shown
zloy xaker [14]

Answer:

y+-1/2x-1

Step-by-step explanation:

The line is negative

It rises one digit and runs 2

and it crosses though -1 on the y axis

4 0
3 years ago
Fffffffffffffffffffffffffffffffffffff<br><br>l
Aleks04 [339]

Answer:

um

Step-by-step explanation:

8 0
3 years ago
A rectangular prism has a width of 51 ft and a volume of 144 ft3. Find the volume of a similar prism with a width of 17 ft. Roun
meriva

Answer:

5.3\ ft^3

Step-by-step explanation:

Similar shapes with scale factor k have proportional volumes with coefficient k^3 i.e.

\dfrac{V_{large}}{V_{small}}=k^3,

where

k=\dfrac{\text{width of large prism}}{\text{width of small prism}}.

Since

\text{width of large prism}=51\ ft,\\ \\\text{width of small prism}=17\ ft,

then

k=\dfrac{51}{17}=3.

Hence,

\dfrac{144}{V_{small}}=3^3\Rightarrow V_{small}=\dfrac{144}{27}=\dfrac{16}{3}=5\dfrac{1}{3}\approx 5.3\ ft^3.

7 0
4 years ago
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