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Marina CMI [18]
2 years ago
13

Luigi uses 39 cups of flour for every 6 pizzas he makes. Complete the table using equivalent ratios.

Mathematics
1 answer:
VikaD [51]2 years ago
6 0
Do 39 divided by 6 and there is your answer
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Answer ASAP<br> Thanks! ;)
Alinara [238K]

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2 years ago
What is the value of the expression –12 – 3 + 9?
yKpoI14uk [10]
<span>–12 – 3 + 9
(-12 - 3) + 9
-15 + 9
-6</span>
5 0
3 years ago
This right rectangular prism is filled with 1/3 -foot unit cubes.
Alex Ar [27]

Answer:

you could just count them

8 0
2 years ago
A grower believes that one in five of his citrus trees are infected with the citrus red mite. How large a sample should be taken
kotegsom [21]

Answer: 68

Step-by-step explanation:

Formula for sample size when prior estimate of population proportion (p) is available:  n=p(1-p)(\dfrac{z^*}{E})^2

, where z*= critical-value.

E= Margin of error.

Let p be the population proportion of  trees are infected with the citrus red mite.

As per given , we have

p=\dfrac{1}{5}=0.2

E= ± 0.08

The critical z-value corresponding to 90% confidence level = z*=1.645

Substitute all the values in the above formula , we get

Required sample size  :n=(0.2)(1-0.2)(\dfrac{(1.645)}{0.08})^2

\Rightarrow\ n=(0.2)(0.8)(20.5625)^2

\Rightarrow\ n=0.16(422.81640625)\\\\\Rightarrow\ n=67.650625\approx68 [Rounded to next integer.]

Thus, the minimum sample size should be taken =68

6 0
3 years ago
An athlete knows that when she jogs along her neighborhood​ greenway, she can complete the route in 10 minutes. It takes 20 minu
IgorLugansk [536]

Answer:

10 miles per hour.

Step-by-step explanation:

Let x represent athlete's walking speed.

We have been given that her jogging rate is 5 mph faster than her walking​ rate, so athlete's jogging speed would be x+5 miles per hour.

\text{Distance}=\text{Rate}\cdot \text{Time}

10 minutes = 1/6 hour.

20 minutes = 1/3 hour

While walking, we will get D_{\text{walking}}=x\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{3}\text{hour}

D_{\text{walking}}=\frac{x}{3}

While jogging, we will get D_{\text{jogging}}=(x+5)\frac{\text{miles}}{\text{hour}}\cdot \frac{1}{6}\text{hour}

D_{\text{jogging}}= \frac{(x+5)}{6}

Since athlete is covering same distance while walking and jogging, so we can equate both expressions as:

\frac{x}{3}=\frac{x+5}{6}

Cross multiply:

6x=3x+15

6x-3x=15

3x=15

\frac{3x}{3}=\frac{15}{3}\\\\x=5

Therefore, athlete's walking speed is 5 miles per hour.

Jogging speed: x+5\Rightarrow 5+5=10

Therefore, athlete's jogging speed is 10 miles per hour.

3 0
3 years ago
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