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goldenfox [79]
3 years ago
15

Sue a tollbooth worker is paid $12.50 per hour between 8 Am and 4 pm. After 4 pm she is paid $14.25 per hour. If Sue works from

10 am to 6 pm one particular day how much money does she earn that day?
Mathematics
2 answers:
katrin2010 [14]3 years ago
7 0

Answer:

She earns that day $103.5

Step-by-step explanation:

Lets explain how to solve the question

- She is paid $12.50 per hour between 8 am and 4 pm

- After 4 pm she is paid $14.25 per hour

- She works one particular day from 10 am to 6 pm

* Lets distribute her time of work into two part according to her

 payment above

# 1st part from 10 am to 4 pm

∵ She is paid $12.50 per hour between 8 am to 4 pm

∵ She works from 10 am to 4 pm

- Calculate how many hours between 10 am and 4 pm

∵ am and pm not like terms in time, so change the time to 24-hours

∵ 4 pm in 24-hour time is 4 + 12 = 16

∴ She works form 10 to 16

∴ She works for 6 hours (16  - 10 = 6)

∴ She is paid = 12.50 × 6 = $75

# 2nd part after 4 pm to 6 pm

∵ She is paid $14.25 per hour after 4 pm

∵ She works from 4 pm to 6 pm

- Calculate how many hours between 4 pm and 6 pm

∵ Both times are pm

∴ She works for 2 hours (6 - 4 = 2)

∴ She is paid = 14.25 × 2 = $28.5

- Add the two answers of the 1st part and the 2nd part

∴ She earns = 75 + 28.5 = $103.5

* She earns that day $103.5

xeze [42]3 years ago
6 0

Answer:

$103.50.

Step-by-step explanation:

From 10 am until 4 pm ( 6 hours) she earns 6 * 12.50 = $75.00.

Then from 4 pm to 6 pm she earns 2*14.25 = $28.50.

Total for that day = 75 + 28.50

= $103.50.

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2. Lorena is trying to choose between two different savings accounts at H-Town Bank. She will deposit $3,500 dollars and will le
Ivahew [28]

Answer:

First of all, this question is not complete. So, we will be hypothetically create two accounts and try to choose the one with the greater profit.

Choice 1 = X = Final Amount after 12 years = $5600

Choice 2 = Y = Final Amount after 12 years = $6285.50

Hence, Lorena should choose choice 2, as it gives more profit over than choice 1.

Step-by-step explanation:

First of all, this question is not complete. So, we will be hypothetically create two accounts and try to choose the one with the greater profit.

Initial Deposit Amount = $3500

Time period = 12 years

Let's Suppose Lorena has two X and Y choices of accounts at H-town Bank.

X = simple interest of 5% over the initial amount for 12 years.

Y = Compound interest 5% over the initial amount for 12 years.

Solution:

Let's calculate the profit for choice 1 = X

Simple interest = 5%

Initial amount = $3500

Time period = 12 years

Formula = A = P (1 + rt)

where, A = Final amount after 12 years

t = time period in years  = 12

P = initial amount to be deposited = $3500

r = annual interest rate = 5%

Plug in the values to get the total amount.

A = 3500(1+0.05x12)

A = $5600 = final amount Lorena will get after 12 years.

Let's calculate the profit for choice 2 = Y

Compound interest = 5%

Initial amount = $3500

Time period = 12 years

Formula = A = P (\frac{r}{n} + 1)^{nt}

where,

A = Final amount after 12 years

t = time period in years  = 12

P = initial amount to be deposited = $3500

r = annual interest rate = 5%

n = number of times interest rate is applied or compounded. = 12

Plug in the values to get the total amount.

A = P (\frac{r}{n} + 1)^{nt}

A = $6285.50

Hence, Lorena should choose choice 2, as it gives more profit over than choice 1.

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2 years ago
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3 years ago
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a triangle has verticals A(-5,-4), B(2,6), C(4,-3) The center of dilation is the origin and (x,y) (3x,3y). what are the vertices
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1 year ago
2. A solar lease customer built up an excess of 6,500 kilowatt hours (kwh) during the summer using his solar
tia_tia [17]

9514 1404 393

Answer:

  a)  E = 6500 -50d

  b)  5000 kWh

  c)  the excess will last only 130 days, not enough for 5 months

Step-by-step explanation:

<u>Given</u>:

  starting excess (E): 6500 kWh

  usage: 50 kWh/day (d)

<u>Find</u>:

  a) E(d)

  b) E(30)

  c) E(150)

<u>Solution</u>:

a) The exces is linearly decreasing with the number of days, so we have ...

  E(d) = 6500 -50d

__

b) After 30 days, the excess remaining is ...

  E(30) = 6500 -50(30) = 5000 . . . . kWh after 30 days

__

c) After 150 days, the excess remaining would be ...

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The supply is not enough to last for 5 months.

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