Answer:
we conclude that the 'bait and switch' technique is not a promotional tactic used by a seller.
Hence, 'a' is the correct option.
Step-by-step explanation:
From the given options, the 'bait and switch' technique is not a promotional tactic used by a seller.
'Bait and switch' is a deceptive sale practice using which the sells try to attract (bait) the customers by offering attractive prices on certain items, but when the customers tend to go to the shop to buy the items, they witness the unavailability of the goods, or find the prices go higher compared to what they had been offered.
Now, since the customers are already present at the shop, the sellers try to pressurize the customer so that they could buy something else.
Therefore, we conclude that the 'bait and switch' technique is not a promotional tactic used by a seller.
Hence, 'a' is the correct option.
Volume of sphere: V(s) = 4/3*pi*R^3 = (4/3)*pi*(D/2)^3 = (1/6) * pi * D^3
Volume of cube: V(c) = s^3
Volume of them is the same, I'm assuming you actually want to know the length of the cubic vertice
So s^3 = (1/6)*pi*D^3 -> s = (1/6 * pi)^1/3 * 6 = (36pi)^1/3
You can just put the 10 over 1 and multiply across. Then simplify! Hope this helps (:
Answer:
The value of x is 8cm. The length of 3 sides are 8cm, 15cm and 17cm.
Step-by-step explanation:
Using Pythagoras' Theorem, a²+b² = c² :
Let a be x cm,
Let b be x+7 cm,
Let c be 2x+1 cm
x² + (x+7)² = (2x+1)²
x² + x² + 14x + 49 = 4x² + 4x + 1
2x² + 14x + 49 = 4x² + 4x + 1
Then, move all the variables to one side and solve it to find the value of x :
4x² + 4x + 1 - 2x² - 14x - 49 = 0
2x² - 10x - 48 = 0
2(x² - 5x - 24) = 0
x² - 5x - 24 = 0
(x-8)(x+3) = 0
x - 8 = 0
x = 8 cm
x + 3 = 0
x = -3 cm (rejected)
Substitute the x value into the length of a,b and c :
a = x
= 8 cm
b = x + 7
= 8 + 7
= 15 cm
c = 2x + 1
= 2(8) + 1
= 16 + 1
= 17 cm
