Tan(– 225°) + sec(-180°)

Brilliant_brown [7]

I remember CUP -- concave up positive. Here we have a leading coefficient that's negative, so the cup is upside down, the parabola opens down, an arch not a bowl.

4 0

3 years ago

At 7:00 am, the temperature was -4℉. At 9:00 am, it was 8° warmer. What was the temperature at 9:00 am? *

Nana76 [90]

4℉.

What we know about Degrees is that there is a Positive type and a negative type.

(i.e: 30℉ is positive and -30℉ is negative.)

If the temperature was -4℉ at 7AM, then it is negative. If it goes up by an amount that is more than 4 then that negative will go up to a positive temperature. In this case: At 9AM it was 8° warmer.

Warmer is a keyword. If it is warmer by an amount, Negative temperatures will go up to a positive and positive temperature will just go up. If it gets cooler, negative temperatures will go down further and positive temperatures will go down to a negative.

So lets work out this problem with our newfound knowledge.

-4° F at 7AM

8° warmer at 9AM

-4 + 8 = 4.

The temperature was 4° at 9AM.

-Snooky

8 0

3 years ago

A jogger goes half a mile north and then turns west. If the jogger finishes 1.3 miles away from the starting point, how far west

Ratling [72]

In order to solve this problem, you must draw a right triangle first to help you visualize the path of the jogger.
You are given 0.5 miles north (which will be the height of the right triangle), and 1.3 miles (which will be the hypotenuse of the triangle).
Using Pythagorean Theorem: a²+b²=c², we have:
0.5² + b² = 1.3²
b = 1.3²-0.5²
b = 1.2 miles

3 0

3 years ago

Number 10Please just show the math and not the sentence explanations, I just want to use this problem as an example :)

Morgarella [4.7K]

Explanation

We are given the following right-angled triangle:

We are required to determine the indicated angle in the given figure.

This is achieved thus:

According to the image, we have:

$\begin{gathered} Opposite=9 \\ Adjacent=21 \end{gathered}$

Therefore, we have:

$\begin{gathered} \tan\theta=\frac{opposite}{adjacent} \\ \tan\theta=\frac{9}{21} \\ \theta=\tan^{-1}(\frac{9}{21}) \\ \theta\approx23\degree \end{gathered}$

Hence, the answer is:

$23\degree$

4 0

1 year ago

Jeremy boiled one cup of water and then let it cool at room temperature. The table shows the temperature, in degrees Fahrenheit,

Volgvan

Answer:How to simplify expressions with exponents and logs. • How to solve equations with ... 15) The temperature, T, of a given cup of hot chocolate after it has been cooling for tminutes can best be modeled by the function ...

Step-by-step explanation:How to simplify expressions with exponents and logs. • How to solve equations with ... 15) The temperature, T, of a given cup of hot chocolate after it has been cooling for tminutes can best be modeled by the function ...

5 0

4 years ago