Yuson used her calculator to solve the equation
2 answers:
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Answer:
The statement is false.
Step-by-step explanation:
For any vector 'r' we have
The magnitude is given by
As we know that the upon squaring a term the result is always positive thus the term in right side of equation i is always positive no matter weather the terms (x,y,z) are positive or negative hence we conclude that magnitude of any vectorial quantity is always positive irrespective of it's direction.
You can re-write this quotient this way :
What's inside the square root must be greater than or equal to 0, because the domain of the square root function is defined on R+ (which is [0,+∞))
In other word we must find x so that :
at the end we get
28(x-1) ≥ 0
28x - 28 ≥ 0
28x ≥ 28
x ≥ 1
So the answer is B, x ≥ 1