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Lubov Fominskaja [6]
3 years ago
10

Tina uses a $50 gift certificate to buy a pair of pajamas for $17.97, a necklace for $25.49, and 3 pairs of socks that each cost

the same amount. Tina has to pay $0.33 because the gift certificate does not cover the total cost of all the items. How much does each pair of socks cost?
Mathematics
2 answers:
Mariana [72]3 years ago
8 0

Answer: $2.18


Step-by-step explanation:

Total amount spent by Tina= $50+$0.33=$50.33

Cost of pajamas=$17.97

Cost of necklace=$25.49

Cost of 3 pairs of socks=\$50.33-\$17.97-\$25.49

=50.33-(17.97+25.49)\\=50-43.46=\$6.54

Thus, cost of 3 pairs of socks= $6.54

Now, cost of 1 pair of socks=\frac{6.54}{3}=\$2.18

Hence the cost of each pair of socks =$2.18


kotegsom [21]3 years ago
7 0
Do 50 minus 17.97 then take that answer and subtract 25.49 and divide that answer by 3 which equals $2.18. $2.18 is the answer 
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Step-by-step explanation:

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  47.25 in² = (3.5 in)(3.5 in + 2h) . . . . use the given values for A, s

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2 years ago
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vovikov84 [41]

Answer:

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Step-by-step explanation:

A probability is said to be unusual if it is lower than 5% of higher than 95%.

We use the normal probability distribution to solve this question.

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

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In this problem, we have that:

\mu = 15.43, \sigma = 2.142

Would it be unusual for a commute time to be between 10 and 11.8 minutes?

The first step to solve this problem is finding the probability that the commute time is between 10 and 11.8 minutes. This is the pvalue of Z when X = 11.8 subtracted by the pvalue of Z when X = 10. So

X = 11.8

Z = \frac{X - \mu}{\sigma}

Z = \frac{11.8 - 15.43}{2.142}

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Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 15.43}{2.142}

Z = -2.54

Z = -2.54 has a pvalue of 0.0055

So there is a 0.0455 - 0.0055 = 0.04 = 4% probability that the commute time is between 10 and 11.8 minutes.

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Upper limit = p + 0.122 = 0.65 + 0.122 = 0.772

95% confidence interval is between 0.528 and 0.772

5 0
2 years ago
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