Answer:
Q (2.5, -4)
Step-by-step explanation:
Let A (1, -5), C = (10, 1), find Q (x, y), so that AQ:QC = 1:5
AQ = (x - 1, y + 5)
QC = (10 - x, 1 - y)
AQ:QC = 1:5
so 5*AQ = QC
5(x - 1) = (10 - x)
5(y + 5) = 1 - y
Solve them:
5x - 5 = 10 - x
6x = 15
x = 15/6 = 2.5
5y + 25 = 1 - y
6y = -24
y = -24/6 = -4
Then answer is Q (2.5, -4)
Answer:
Final answer is A. 
Step-by-step explanation:
From table we see that there are 7 places in the list.
Event A = The place is city.
Then
indicates the place is NOT city.
From table we see that there are 4 names "India, Peru, Canada, Mexico" which are not city.
Hence probability that the chosen place is not city is given by:

Hence final answer is A. 
6square root of 3 (numerator) over÷ square root of 3 and square root of 3. Then you get 6 square root of 3 over ÷ 3=2 square root of 3.
Take time mate) Good day.
Answer:
the probability is 0.02 (2%)
Step-by-step explanation:
defining the event S= the message is spam , then the probability is
P(S) = probability that a randomly selected message comes from account #1 * probability that the message is spam given that the message is from account #1 + probability that a randomly selected message comes from account #2 * probability that the message is spam given that the message is from account #2 + probability that a randomly selected message comes from account #3 * probability that the message is spam given that the message is from account #3 = 0.6 * 0.01 + 0.3 * 0.03 + 0.1 * 0.05 = 0.02 (2%)
thus the probability is 0.02 (2%)
9.58 = 9 58/100 = 9 29/50