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Eva8 [605]
3 years ago
13

What is 4(6x + 11)? What I mean is how do you find the answer to this and what is the answer

Mathematics
2 answers:
alex41 [277]3 years ago
8 0
Well that is an expression not an equation so it has no answer as you typed it.
You can expand it by carrying out the indicated multiplication if you'd like:

4(6x)+4(11)

24x+44
irinina [24]3 years ago
4 0
4 times 6 equals 24 plus 11 equals 35
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Thank you, will give brainliest.
slamgirl [31]
(7,6) is the answer of your question
Please mark as brainiest 
4 0
3 years ago
Write an equation for a quadratic function that has x intercepts (-3, 0) and (5, 0)
Blizzard [7]

Answer:

One possible equation is f(x) = (x + 3)\, (x - 5), which is equivalent to f(x) = x^{2} - 2\, x - 15.

Step-by-step explanation:

The factor theorem states that if x = x_{0}  (where x_{0} is a constant) is a root of a function, (x - x_{0}) would be a factor of that function.

The question states that (-3,\, 0) and (5,\, 0) are x-intercepts of this function. In other words, x = -3 and x = 5 would both set the value of this quadratic function to 0. Thus, x = -3\! and x = 5\! would be two roots of this function.

By the factor theorem, (x - (-3)) and (x - 5) would be two factors of this function.

Because the function in this question is quadratic, (x - (-3)) and (x - 5) would be the only two factors of this function. In other words, for some constant a (a \ne 0):

f(x) = a\, (x - (-3))\, (x - 5).

Simplify to obtain:

f(x) = a\, (x + 3)\, (x - 5).

Expand this expression to obtain:

f(x) = a\, (x^{2} - 2\, x - 15).

(Quadratic functions are polynomials of degree two. If this function has any factor other than (x - (-3)) and (x - 5), expanding the expression would give a polynomial of degree at least three- not quadratic.)

Every non-zero value of a corresponds to a distinct quadratic function with x-intercepts (-3,\, 0) and (5,\, 0). For example, with a = 1:

f(x) = (x + 3)\, (x - 5), or equivalently,

f(x) = x^{2} - 2\, x - 15.

6 0
2 years ago
In a right triangle one acute angle measures 48 more than 2 times the other. If the sum of the measure of the two acute angles m
Ainat [17]

A given angle measures 90°.. Then, note that the total measurement of the triangle is 180°... Subtract 180° by 90°, and the other angles must add up to 90°!  

Good luck!


3 0
3 years ago
Quadrilateral ABCD is a square with diagonals that intersect at point E. Find angle ADB. A. 11.25º B. 22.5º C. 45º D. 90º
never [62]

IT WOULD BE "D" I BELIEVE

HOPE IM RIGHT AND THIS HELPS


7 0
3 years ago
Read 2 more answers
Please help me find the area of each shaded segment and round the answer to the nearest tenth :)
Keith_Richards [23]
Hi there!

In order to solve, we need to use the formula for the area of a circle, and the angle given to find the area of the sector. Then, subtract the area of the triangle to find the area of the segment. We would use the equation : A = x/360 (pi * r^2) - 1/2(b * h). We need to plug in 90 for the angle measurement, 8 for the radius, and 8 for both the base and height. 

WORK:
A = 90/360 (pi * 64) - 1/2(64)
A = 1/4(64pi) - 32
A = 16pi - 32 = ~ 18.3ft^2

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!

3 0
3 years ago
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