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Law Incorporation [45]
3 years ago
8

What is y=3x^2-2 in vertex form

Mathematics
1 answer:
Nata [24]3 years ago
3 0
\bf \qquad \qquad \textit{parabola vertex form}
\\\\\\
y=a(x-{{ h}})^2+{{ k}}\\
x=a(y-{{ k}})^2+{{ h}}\qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-----------------------------\\\\
y=3x^2-2\iff y = 3(x-0)^2-2
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From the diagram below, if the sides AD = 3 and DC = 27, and BD = X + 3, find x.
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Given:

• AD = 3

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• DC = 27

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• BD = x + 3

Let's solve for x.

To solve for x, apply the altitude formula:

\frac{AD}{BD}=\frac{BD}{DC}

Where BD is the altitude.

Cross multiply:

BD^2=AD*DC

Plug in the values and solve for x:

\begin{gathered} (x+3)^2=3*27 \\  \\ (x+3)^2=81 \end{gathered}

Take the square root of both sides:

\begin{gathered} \sqrt{(x+3)^2}=\sqrt{81} \\  \\ x+3=9 \\  \\ \text{ Subtract 3 from both sides:} \\ x+3-3=9-3 \\  \\ x=6 \end{gathered}

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ANSWER:

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