Ask question

Ask question

All categories

Bad White [126]

3 years ago

7

One triangular face of the prism shown has an interior angle with a measure of 65° and an exterior angle with a measure of 120°.

What is the measure of the marked interior angle?
A.25°
B.45°
C.55°
D.65°

2 answers:

PolarNik [594]3 years ago

7 0

Answer:

55

Step-by-step explanation:

120 - 65 = 55

Marysya12 [62]3 years ago

6 0

Sussy among us sussy baka

You might be interested in

I really need some help it's hard to understand!

Vedmedyk [2.9K]

C you just add them divide by 2

8 0

4 years ago

Read 2 more answers

Give a power series representation for the function f(x) x^3/(1 + 9x^2)

Nata [24]

Recall that for $|x|$ , we have

$\displaystyle\frac1{1-x}=\sum_{n\ge0}x^n$

Replace $x$ with $-9x^2$ and we get

$\displaystyle\frac1{1-(-9x^2)}=\sum_{n\ge0}(-9x^2)^n=\sum_{n\ge0}(-9)^nx^{2n}$

Lastly, multiply this by $x^3$ , so that

$\boxed{f(x)=\displaystyle\sum_{n\ge0}(-9)^nx^{2n+3}}$

6 0

4 years ago

5. AC bisects Angle BAD. Find the measure of angle BAC.

alukav5142 [94]

If AC bisects < BAD, it means it cuts it into 2 equal parts

so < BAC = < CAD

3x + 12 = 5x
12 = 5x - 3x
12 = 2x
12/2 = x
6 = x

< BAC = 3x + 12.......3(6) + 12 = 30 degrees <===

6 0

3 years ago

What are the coordinates of the vertex of the function f(x)=x^2+10x−3? (–5, –28) (–5, 28) (5, –28) (5, 28)

polet [3.4K]

Answer:

(-5,-28)

Step-by-step explanation:

Given

$f(x)=x^2+10x - 3$

Required

Find the coordinates of the vertex

Given that the function is a quadratic function;

The general form of a quadratic function is

$f(x)= ax^2+bx +c$

By comparison;

$a = 1\ b = 10\ and\ c = -10$

To calculate the coordinates of the vertex;

we start by calculating the x-coordinate;

$x = \frac{-b}{2a}$

Substitute 10 for b and 1 for a

$x = \frac{-10}{2*1}$

$x = \frac{-10}{2}$

$x = -5$

Substitute $x = -5$ in the given function;

$y=x^2+10x - 3$

$y=(-5)^2+10*-5 - 3$

$y=25-50 - 3$

$y=-28$

<em>Hence, the coordinates of the vertex is (-5,-28)</em>

6 0

4 years ago

Two researchers conducted a study in which two groups of students were asked to answer 42 trivia questions from a board game. Th

Verizon [17]

Answer:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

Step-by-step explanation:

We know the following info:

$\bar X_1 = 21.9$ sample mean for group 1

$\bar X_2 = 19.8$ sample mean for group 2

$s_1 = 3.4$ sample standard deviation for group 1

$s_2 = 3.5$ sample standard deviation for group 2

$n_1 = 200$ sample size group 1

$n_2 = 200$ sample size group 2

We want to find a confidence interval for the difference of means and the correct formula to do this is:

$(\bar X_1 -\bar X_2) \pm t_{\alpha/2} \sqrt{\frac{s^2_1}{n_1} +\frac{s^2_2}{n_2}}$

Now we just need to find the critical value. The confidence level is 0.95 then the significance is $1-0.95 =0.05$ and $\alpha/2 =0.025$ . The degrees of freedom are given by:

$df= n_1 +n_2 -2= 200+200-2= 398$

The critical value for this case would be : $t_{\alpha/2}=1.966$

And replacing into the confidence interval formula we got:

$(21.9-19.8) -1.966\sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 1.422$

$(21.9-19.8) -1.966 \sqrt{\frac{3.4^2}{200} +\frac{3.5^2}{200}}= 2.778$

And we are 95% confident that the true difference means are between $1.422 \leq \mu_1 -\mu_2 \leq 2.778$

5 0

3 years ago