So lets try to prove it,
So let's consider the function f(x) = x^2.
Since f(x) is a polynomial, then it is continuous on the interval (- infinity, + infinity).
Using the Intermediate Value Theorem,
it would be enough to show that at some point a f(x) is less than 2 and at some point b f(x) is greater than 2. For example, let a = 0 and b = 3.
Therefore, f(0) = 0, which is less than 2, and f(3) = 9, which is greater than 2. Applying IVT to f(x) = x^2 on the interval [0,3}.
Learn more about Intermediate Value Theorem on:
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Answer: No solution for V. No solution.
Step-by-step explanation:
-v+5+6v=1+5v+3
Combine like terms together by adding all of the v's together, and number together.
5v+5=4+5v
5v-5v+5=4
0+5=4
5=4
Since this is a false statement, then no solution for V
Answer:
What is the question to this
Step-by-step explanation:
Answer:
257.25
Hope This Helps! Have A Nice Day!!
Answer:
y=(1/9)x+4
Step-by-step explanation:
x=3b
b=(1/3)x
y=2/6(1/3)x+4
y=(2/18)x+4
y=(1/9)x+4
