Which of these devices is usually the default gateway for most home networks?

Suppose x and y are int variables and ch is a char variable. Consider the following input: 5 28 36 What value (if any) is assign

eimsori [14]

Answer:

x is assigned "5", y is assigned "28", and ch is assigned "$"

Explanation:

#include <stdio.h>

#include <iostream>

using namespace std;

int main()

{

int x,y;

char ch;

x = 5;

y = 28;

ch = 36;

cout<<x<<endl<<y<<endl;

cout<<ch;

return 0;

}

4 0

3 years ago

Which of the following is a step in paraphrasing? Skim the original information to get a sense of what it is about. Select a few

Sedaia [141]

Select a few key words to change to your own words

4 0

3 years ago

Read 2 more answers

A 4-bit left shift register is initially in the 0000 state, with all the flip flops storing 0s. A group of bits 1011 is serially

frutty [35]

Answer:

0010

Explanation:

Serially left shifted means that the left most bit will enter the register first. The left most bit already stored in the register will move out of the sequence. The "bold" bits mentioned below highlight these left most bits:

Initial State of the Register:

0000

Group of bits entering:

1011

First Clock Cycle:

0000 (This bold bit will move out)

1011 (This bold bit will move in from right side, shifting the whole sequence one place to the left).

The resulting Sequence:

0001

Second Clock Cycle:

0001 (This bold bit will move out)

1011 (This bold bit will move in from right side, shifting the whole sequence one place to the left).

The resulting Sequence:

0010 (Final Answer)

6 0

4 years ago

What is output?

Alex777 [14]

Answer:

The output of this question is 21. As show in the image

The explanation is given in below

Explanation:

Let first write the question

C=1

sum = 0

while(C<10):

C=C+3

sum=sum + C

print(sum)

Now Focus on

while(C<10):

C=C+3

sum=sum + C

The value of C is initially 1

C=1+3

Sum= 0+4

In second loop the value of C will become 4

c=4+3

sum=4+7

In third loop the value of C will be 7

c=7+3

sum=11+10

so the answer is 11+10=21

7 0

3 years ago

. In the BorderLayout class, what are NORTH, SOUTH, EAST, WEST, and CENTER?

ycow [4]

Answer:

A BorderLayout corresponds to a layout type where the components are organized along geographical directions represented by NORTH, SOUTH, EAST, WEST, and CENTER.

Explanation:

The layout class is awt determines the actual placement of components in the user interface. BorderLayout is a layout where the components are organized along geographical directions represented by NORTH, SOUTH, EAST, WEST, and CENTER. For example:

Panel p = new Panel();

p.setLayout(new BorderLayout());

p.add(new TextArea(), BorderLayout.CENTER);

p.add(new Button("Close"), BorderLayout.SOUTH);

This code segment will add a textarea at the CENTER of the interface and a button 'Close' towards the SOUTH.

8 0

3 years ago