What is the restriction of x^2-6x+5/x^2-3x-10

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

Answer:

x ≠ - 2, 5

Step-by-step explanation:

The restrictions occur in the denominator which cannot be zero as this would make the function undefined. Equating the denominator to zero and solving gives the values that x cannot be.

solve x² - 3x - 10 = 0 ⇒ (x - 5(x + 2) = 0 ⇒ x = -2, 5

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ss7ja [257]

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2 years ago

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Gwar [14]

We can use the Сosine formula to solve this problem.
First we must find the third side (АС) of the triangle:

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The smallest angle of the triangle lies opposite the smallest side, so we need to find m∠C.

$cosC= \frac{AC^2+BC^2-AB^2}{2*AC*BC} \\ \\ cosC= \frac{12.67^2+11^2-8^2}{2*12.67*11}= \frac{160.53+121-64}{278.74} = \frac{217.53}{278.74} \approx 0.7804$

Now we can use Bradis's Table (I don't know the name in English, maybe Trigonometric Table?) to find m∠C:

m∠С = 38°42' = 38.7°

Answer: 38.7°

I hope this helps