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mamaluj [8]
3 years ago
12

Answer the following questions for each geometric

Mathematics
1 answer:
viva [34]3 years ago
6 0

Answer:

10

0.1

100/9,11.111

1500

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Alchen [17]
9.01 * 10^3 in scientific notation is 9.01 * 10^3.

I got this answer by moving the decimal so there is a non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent of the 10. If the decimal is binge move to the right, the exponent will be negative, but if the decimal is being moved to the left the exponent will be positive.

I hope this helps! :>
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What’s the answer and work for this?
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4 years ago
Laser scanning for fish volume estimation. engineers design tanks for rearing commercial fish to minimize both the use of natura
AVprozaik [17]

Answer:

The 99% confidence interval would be given by (196.2;283.8)

We are 99% condident that the true mean is between 196.2 and 283.8  

We need to assume that the data comes from a random sample and we need to assume that the distribution of the data is normal.  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=240 represent the sample mean for the sample  

\mu population mean (variable of interest)

s=15 represent the sample standard deviation

n=4 represent the sample size  

Part a

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=4-1=3

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,3)".And we see that t_{\alpha/2}=5.84

Now we have everything in order to replace into formula (1):

240-5.84\frac{15}{\sqrt{4}}=196.2    

240+5.84\frac{15}{\sqrt{4}}=283.8

So on this case the 99% confidence interval would be given by (196.2;283.8)    

We are 99% condident that the true mean is between 196.2 and 283.8

What assumption about the data is necessary for the inference derived from the analysis to be valid?

We need to assume that the data comes from a random sample and we need to assume that the distribution of the data is normal.

4 0
3 years ago
Each of 7 students reported the number of movies they saw in the past year. Here is what they reported.
SIZIF [17.4K]

Answer:

mean=12

Step-by-step explanation:

First, order the data like so.

5, 7, 12, 12, 16, 17, 17

Then add them all up.  

It is a sum of 86.

Finally divide

86/7=12.2

Since 12.2 movies aren't possible, let's say the mean is 12

3 0
3 years ago
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