The answer is B I believe
The sample space of an experiment is the set of all possible outcomes for that experiment. You may have noticed that for each of the experiments above, the sum of the probabilities of each outcome is 1. This is no coincidence. The sum of the probabilities of the distinct outcomes within a sample space is 1.
Answer: x=4, x=-5
Step-by-step explanation:
![\frac{x}{x-4}-\frac{4}{x+5}=\frac{36}{x^2+x-20}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx-4%7D-%5Cfrac%7B4%7D%7Bx%2B5%7D%3D%5Cfrac%7B36%7D%7Bx%5E2%2Bx-20%7D)
Multiply everything by the LCM = (x-4)(x+5):
![\frac{x}{x-4}\left(x-4\right)\left(x+5\right)-\frac{4}{x+5}\left(x-4\right)\left(x+5\right)=\frac{36}{x^2+x-20}\left(x-4\right)\left(x+5\right)](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7Bx-4%7D%5Cleft%28x-4%5Cright%29%5Cleft%28x%2B5%5Cright%29-%5Cfrac%7B4%7D%7Bx%2B5%7D%5Cleft%28x-4%5Cright%29%5Cleft%28x%2B5%5Cright%29%3D%5Cfrac%7B36%7D%7Bx%5E2%2Bx-20%7D%5Cleft%28x-4%5Cright%29%5Cleft%28x%2B5%5Cright%29)
![\frac{x\left(x-4\right)\left(x+5\right)}{x-4} -\frac{4\left(x-4\right)\left(x+5\right)}{x+5} =\frac{36\left(x-4\right)\left(x+5\right)}{\left(x-4\right)\left(x+5\right)}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%5Cleft%28x-4%5Cright%29%5Cleft%28x%2B5%5Cright%29%7D%7Bx-4%7D%20-%5Cfrac%7B4%5Cleft%28x-4%5Cright%29%5Cleft%28x%2B5%5Cright%29%7D%7Bx%2B5%7D%20%3D%5Cfrac%7B36%5Cleft%28x-4%5Cright%29%5Cleft%28x%2B5%5Cright%29%7D%7B%5Cleft%28x-4%5Cright%29%5Cleft%28x%2B5%5Cright%29%7D)
Simplify by cancelling out same terms: in the numerators and denominators:
![x\left(x+5\right)-4\left(x-4\right)=36](https://tex.z-dn.net/?f=x%5Cleft%28x%2B5%5Cright%29-4%5Cleft%28x-4%5Cright%29%3D36)
![x^2+x-20=0](https://tex.z-dn.net/?f=x%5E2%2Bx-20%3D0)
(x+5)(x-4) = 0
The solution to the quadratic equation is x=4, x=-5
Answer:
y=3x+5
Step-by-step explanation:
easy math❤
(x+11)÷2 Would be how to write it, replace x with any number