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3 years ago

Explain it so I can better understand it

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

6 0

The question is essentially asking who's equation works better (Part A) and to explain why (Part B).
Marcella is suggesting the equation 6r + 12 = 683.88
Julia is suggesting the equation 6(r + 12) = 683.88

Six people are on the trip.
It is $12 PER person to rent a floatation device.
The total cost of the trip was $683.88.

Hope I've helped!

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How does the mean absolute deviation (MAD) of the data in set 1 compare to the mean absolute deviation of the data in set 2?

denis-greek [22]

Answer:

the answer is C

Step-by-step explanation:

if you do 5+10+7+2 you get 24 divide by 4 you get 6 mean is 6 for set 1

Set 2 if you do 5+10+7+42 you get 64 divide by 4 and you get 16 16-10.5 you get so 5.5 set is less than set 2 there ya go dude

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3 years ago

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Given: ABCD is a trapezoid, AC ⊥ CD AB = CD, AC=the square root of 75 , AB = 5 Find: AABCD

Ugo [173]

In this attached picture according to the conditions of the problem we have an isosceles trapezoid and since we know that legs are equal (AD=BC=5 cm), we have to calculate bases and height in order to find the area. Working with the triangle BCD, we apply Pythagoras theorem and find that CD = $\sqrt{75+25}$ = 10 cm. Since BDC is a right triangle, applying theorem for the area of triangles, we find that $\frac{1}{2} * BF = \frac{1}{2} * 5 * \sqrt{75}$ and BF= $0.5\sqrt{75}$ . Since ABCD is an isosceles trapezoid, triangles ADE and BFC are congruent with Angle Side Angle theorem. Then, DE=FC and with the help of Pythagoras theorem, DE=FC=2.5 cm. Then, AB=EF=5 cm and the area of the trapezoid is $A= BF * \frac{AB+CD}{2} = 0.5 \sqrt{75} * \frac{5+10}{2} = 18.75 \sqrt{3} cm^{2}$

3 0

3 years ago

Max is stacking logs at his campground for firewood. After his first load of logs, he has 12 logs on the stack. After his sevent

Natasha2012 [34]

Answer:

Let L(n) be the function that gives the amount of logs stacked after n loads.

L(n) = 12 + 8(n-1)

Step-by-step explanation:

Let L(n) be the function that gives the amount of logs stacked after n loads.

Let's call for the moment the first load as L(0)

L(0)= 12

Let r be the number of logs carried in each load, then

L(n) = 12 + nr

Since L(6) (the seventh load) equals 60, we have

60 = 12 + 6r, and r = 8.

So a function for the number of loads starting from n=0 would be

L(n) = 12 + 8n

If we want to start with n=1, we simply change the variable

L(n) = 12 + 8(n-1) (n=1,2,3,...).

So L(1) = 12, L(2) = 20, L(3) = 28,...L(7) = 60 and so on.

7 0

3 years ago

One, no, or infinitely many solutions

rusak2 [61]

Answer:

Only one solution

Step-by-step explanation:

Given:

2c + 4 - 3c = -9 + c + 5

Find:

Number of solution

Computation:

2c + 4 - 3c = -9 + c + 5

-c + 4 = -4 + c

-2c = -8

c = 4

Only one solution

6 0

3 years ago