The sum will be x+y because their ages are variables.
|DF| = |DE| + |EF|
|DF| = 9x -36
|DE| = 47
|EF| = 3x+10
Substitute:
9x - 39 = 47 + 3x + 10
9x - 39 = 3x + 57 |+39
9x = 3x + 96 |-3x
6x = 96 |:6
x = 16
Put the value of x to the equation |EF| = 3x + 10
|EF| = (3)(16) + 10 = 48 + 10 = 58
Answer: |EF| = 58
Answer:
Isolate the variable by dividing each side by factors that don't contain the variable.
x = −
3
Step-by-step explanation:
Answer:
3.8 seconds
Step-by-step explanation:
Given equation
When the ball hits the ground then height is 0
So we replace h with 0 and solve for t
a= -16 , b= 60 and c= 5
Apply quadratic formula to solve for t
=![\frac{-60+\sqrt{60^2-4\left(-16\right)\cdot \:5}}{2\left(-16\right)}[/tex[tex]=\frac{-60+-\sqrt{3920}}{-32}](https://tex.z-dn.net/?f=%5Cfrac%7B-60%2B%5Csqrt%7B60%5E2-4%5Cleft%28-16%5Cright%29%5Ccdot%20%5C%3A5%7D%7D%7B2%5Cleft%28-16%5Cright%29%7D%5B%2Ftex%3C%2Fp%3E%3Cp%3E%5Btex%5D%3D%5Cfrac%7B-60%2B-%5Csqrt%7B3920%7D%7D%7B-32%7D)
Now make two fractions and solve for x
t= 
=-0.0815
t= 
=3.83
So answer is 3.8 seconds
X is 0 so that means you answer would be 3+0=3
