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4 years ago

What is the definition of liquidity?

1 answer:

8 0

The availability of liquid assets to a market or company.<span>liquid assets; cash.a high volume of activity in a market.</span>

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A real estate broker acting as a property manager leased a building for 10 years at an annual rent of 48,000. They will receive

Eddi Din [679]

Answer:

Question... is the commission given 10 times or 3?

If the commission is 10 then

5*(48,000 * .075) + 3*(48,000 * .05) +2*(48,000 * .035)

5*(3600) + 3*(2400) +2*(1680)

= 28560

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

If the commission is 3 then (once for first five years, once for the next three,

and once for the last two

(48,000 * .075) + (48,000 * .05) +(48,000 * .035)

=7680

Step-by-step explanation:

6 0

3 years ago

GIVING BRAINLIEST! Calculate the slope of the following line

Georgia [21]

The slope is 3 because if you find the rise and run of two points. Run=1 rise=3 (divide the rise by the run) which equals 3. The slope is 3

6 0

3 years ago

Can some one solve this in long division

Hoochie [10]

1.3
5.51
8.2
7.5
2.5
4.12
2.25
3.25
5.12
7.30
thats all i know

4 0

4 years ago

Describe how to mentally calculate 1/10 of $12.50

ivanzaharov [21]

Mentally your dividing the 12.50 by 10 and then thats 1/10 of it.

6 0

4 years ago

A fair six-sided die, with sides numbered 1 through 6, will be rolled a total of 15 times. Let x¯1 represent the average of the

Anna35 [415]

Answer:

option B

Step-by-step explanation:

$P(x =x) [{\frac{1}{6} ;x =1,2,3...6]$

$E (x) = \frac{6+1}{2} =\frac{7}{2} =3.5\\\\E(x)=3.5$

Given random experiment of tossing of 6 sided dice is follow above distribution

Therefore, suppose x₁, x₂ ...x₁₀ are 10 independent and indentical random variable which represent first 10 rolls

Average of first 10 rows equals

$\bar x_1 =\frac{ \sum ^{10}_{i=1}xi}{10}$

$E(\bar x_1)=\frac{ \sum ^{10}_{i=1}E(x_1)}{10} \\\\=\frac{10(3.5)}{10} \\\\=3.5\\\\E(\bar x_1) = 3.5----(1)$

now suppose ,

x₁₁,x₁₂, ...x₁₅ are 5 independent and identical random variable which represent last 5 roll

average of last 5 roll is

$E(\bar x_2)= \frac{ \sum ^{5}_{i=1}xi}{5} \\\\= \frac{5 \times(3.5)}{5} \\\\=3.5$

Therefore, $\bar x_1 - \bar x_2$

3.5 - 3.5 = 0

5 0

3 years ago