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Mariana [72]
2 years ago
5

Think about all of the ways in which a circle and a parabola can intersect.

Mathematics
1 answer:
xeze [42]2 years ago
7 0

There will be four ways a circle and a parabola can intersect because the solution of the quartic equation will be 4.

<h3>What is a circle?</h3>

It is described as a set of points, where each point is at the same distance from a fixed point (called the center of a circle)

We have a circle and a parabola:

As we know the standard form of a circle:

\rm (x-h)^2 +(y-k)^2=r^2

The standard form of the parabola:

\rm y = a(x-h)^2+k  

If we plug the value of y from the parabola equation in the circle equation, we get a quartic equation(4th order equation)

The solution of the quartic equation will be 4.

Thus, there will be four ways a circle and a parabola can intersect because the solution of the quartic equation will be 4.

Learn more about circle here:

brainly.com/question/11833983

#SPJ1

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If you a 1hour long test and you have 10 question home many minutes would you spend on each question if you used the whole hour
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When i am solving for the sides of a right triangle when will i use trigonometric functions
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The ratios of the sides of a right triangle are called trigonometric ratios. We need to use trigonometric functions to find them when we don't have any angle other than 90 degree shown.

Three common trigonometric ratios are the sine (sin), cosine (cos), and tangent (tan). These are defined for acute angle.

However when we have one angle given with the 90 degree we can deduct without trigonometry but we would use all angles to find the hypotenuse or all angles to find the side of a right angle.

Alternatively, we cna do this with one given angle but if we have one, we might as well work out the other one without trigonometry and do a division with Sin = 25 (sin 35) sin 90  / sin 55

is one example when given the base 25ft that would find the hypotenuse or the length of elevation for buildings looking down or zip-wire questions.

Step-by-step explanation:

       A

       |  \

       l     \

4cm|        \ 5cm

       |          \

       |            \

   B | -  -  -  -  \ C      

          3cm

Suppose we wanted to find sin( A) in△ABC    

(The height of the wall in elevation questions would be used above the base shown 3cm at the start) Sin = 3 (sin 35)° sin 90°  / sin 55° to find the height side (4).

Sine is defined as the ratio of the opposite to the hypotenuse

sin(A) =  hypotenuse          ​= AB/BC        = 3/5

             / opposite

                                           

​

​

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