Answer:
C is the answer to this question.
Answer:
2^11
Explanation:
Physical Memory Size = 32 KB = 32 x 2^10 B
Virtual Address space = 216 B
Page size is always equal to frame size.
Page size = 16 B. Therefore, Frame size = 16 B
If there is a restriction, the number of bits is calculated like this:
number of page entries = 2^[log2(physical memory size) - log2(n bit machine)]
where
physical memory size = 32KB which is the restriction
n bit machine = frame size = 16
Hence, we have page entries = 2^[log2(32*2^10) - log2(16)] = 2ˆ[15 - 4 ] = 2ˆ11
Explanation:
public class Int_List
{
protected int[] list;
protected int numEle = 0;
public Int_List( int size )
{
list = new int[size];
public void add( int value )
{
if ( numEle == list.length )
{
System.out.println( "List is full" );
}
else
{
list[numEle] = value;
numEle++;
}
}
public String toString()
{
String returnStr = "";
for ( int x = 0; x < numEle; x++ )
{
returnStr += x + ": " + list[x] + "\n";
}
return returnStr;
}
}
public class Run_List_Test
{
public static void main( String[] args )
{
Int_List myList = new Int_List( 7 );
myList.add( 102 );
myList.add( 51 );
myList.add( 202 );
myList.add( 27 );
System.out.println( myList );
}
}
Note: Use appropriate keyword when you override "tostring" method
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