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oksano4ka [1.4K]
2 years ago
14

Help ASAP!!! During which phase of a well-structured study session is each occurring?

Computers and Technology
2 answers:
gladu [14]2 years ago
7 0

Answer:

1. drill

2. discuss

3. review

4. prepare

Explanation:

Your Welcome!

BartSMP [9]2 years ago
7 0

Answer:

1. drill

2. discuss

3. review

4. prepare

Explanation:

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hram777 [196]

Answer:

Just Click Log out!

Explanation:

Its Simple, really! I promise its real

5 0
3 years ago
Read 2 more answers
Write a function to sum the following series:
Phoenix [80]

Answer:

<u>C program to find the sum of the series( 1/2 + 2/3 + ... + i/i+1)</u>

#include <stdio.h>

double m(int i);//function declaration  

//driver function

int main() {

int i;

printf("Enter number of item in the series-\n");//Taking input from user

scanf("%d",&i);

double a= m(i);//Calling function

printf("sum=%lf",a);

return 0;

}

double m(int i)//Defining function

{

double j,k;

double sum=0;

for(j=1;j<i+1;j++)//Loop for the sum

{

k=j+1;

sum=sum+(j/k);

}

return sum;

}

<u>Output:</u>

Enter number of item in the series-5

sum=3.550000

5 0
3 years ago
Suppose users share a 1-Gbps link. Also, suppose each user requires 200 Mbps when transmitting, but each user only transmits 30
V125BC [204]

Answer:

The answer is "5 users and 1 block".

Explanation:

In Option a:

Bandwidth total = 1-Gbps \times 1000

                          = 1,000 \ Mbps      

Any User Requirement = 200 \ Mbps

The method for calculating the number of approved users also is:  

Now, calculate the price of each person for overall bandwidth and demands,  

\text{Sponsored user amount} = \frac{\text{Bandwidth total}}{\text{Each user's requirement}}

                                     =\frac{1000}{200}\\\\=\frac{10}{2}\\\\= 5 \ users

In Option b:

\text{blocking probability} = \frac{link}{\text{1-Gbps} = 10^9 \frac{bits}{sec}}

\ let = 0.05 = \frac{100}{20} \\\\\text{blocking probability} = \frac{ 200 \times 10^6}{\frac{100}{20}}

                                = \frac{ 200 \times 10^6 \times 20 }{100}\\\\= \frac{ 2 \times 10^6 \times 20 }{1}\\\\= 40 \times 10^6 \\\\

mean user = 25 \times \frac{1}{20} \\\\

                  = 1.25

max user = \frac{10^9}{40 \times 10^6} \\\\

                = \frac{10^9}{4 \times 10^7} \\\\ = \frac{10^2}{4} \\\\ = \frac{100}{4} \\\\= 25 \\\\ =\ \ 1 \ \ block \\\\

3 0
3 years ago
Juan is a network administrator and must set up a VPN for his company's network. To allow safe communication, he should
Mekhanik [1.2K]

Answer:

select Control Panel, then Network Protocols, then Internet

4 0
2 years ago
Identify the operation which is NOT one of the parts of the fivebasic set operations in relational algebra?
wariber [46]

Answer:

Join

Explanation:

Five basic set operators in relational algebra are as follows:

  • Selection - tuple selection
  • Projection - extract columns
  • Cartesian product - cross product of relations
  • Set union - union of two relations
  • Set difference - minus operation on two relations

As we can see, Join is not part of the basic set operations but it is implemented using the Cartesian Product operator.

5 0
3 years ago
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