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oksano4ka [1.4K]
3 years ago
14

Help ASAP!!! During which phase of a well-structured study session is each occurring?

Computers and Technology
2 answers:
gladu [14]3 years ago
7 0

Answer:

1. drill

2. discuss

3. review

4. prepare

Explanation:

Your Welcome!

BartSMP [9]3 years ago
7 0

Answer:

1. drill

2. discuss

3. review

4. prepare

Explanation:

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You are working on a graphical app, which includes multiple different shapes. The given code declares a base Shape class with an
ycow [4]

Answer:

maybe

Explanation:

5 0
3 years ago
c++ 2.30 LAB: Phone number breakdown Given a long long integer representing a 10-digit phone number, output the area code, prefi
Nady [450]

Answer:

#include <iostream>

using namespace std;

int main()

{

   //declare variable to store phone numbers,its area code, prefix and line number.

   long phone_number;

   int area_code, prefix,line_number;

   cout<<"Enter 10-digit phone number:"<<endl;

   //input 10-digit phone number

   cin>>phone_number;

   //logic to find area_code, prefix, and line_number.

   area_code = phone_number/10000000;

   prefix = (phone_number/10000)%1000;

   line_number = phone_number%10000;

   //output phone number in asked format.

   cout<<area_code<<"-"<<prefix<<"-"<<line_number<<endl;

   return 0;

}

Output:

Enter 10-digit phone number:

8005551212

800-555-1212

Explanation:

In the above program 10 digit phone number entered by user will be stored in the variable phone_number.

Then using this phone_number variable area_code, prefix, and line number are calculated using the following logic:

area_code = phone_number/10000000;

prefix = (phone_number/10000)%1000;

line_number = phone_number%10000;

Finally these area_code, prefix, and line_number are displayed with hyphen in between using cout statement.

5 0
3 years ago
How could the following line of code be shortened?
Alinara [238K]

Answer:

2

Explanation:

The second option is the only one that will work. The last would work but doesn't make the code any shorter.

8 0
2 years ago
In the code snippet below, pick which instructions will have pipeline bubbles between them due to hazards.
denpristay [2]

Answer:

b. lw $t4, 4($t0)

c. add $t3, $t5, $t4

Explanation:

Pipeline hazard prevents other instruction from execution while one instruction is already in process. There is pipeline bubbles through which there is break in the structural hazard which preclude data. It helps to stop fetching any new instruction during clock cycle.

7 0
3 years ago
Write a method called findNames that meets the following specs: It takes two arguments: a list of strings, allNames, and a strin
Anna11 [10]

Answer:

public class Solution {

   public static void main(String args[]) {

       String[] allNames = new String[]{"Bob Smith", "Elroy Jetson", "Christina Johnson", "Rachael Baker", "cHRis", "Chris Conly"};

       String searchString = "cHRis";

       

       findNames(allNames, searchString);

   }

   

   public static void findNames(String[] listOfName, String nameToFind){

       ArrayList<String> resultName = new ArrayList<String>();

       

       for(String name : listOfName){

           if (name.toLowerCase().contains(nameToFind.toLowerCase())){

               resultName.add(name);

           }

       }

       

       for(String result : resultName){

           System.out.println(result);

       }

   }

}

Explanation:

The class was created called Solution. The second line define the main function. Inside the main function; we initialized and assign an array called allNames to hold the list of all name. Then a String called searchString was also defined. The searchString is the string to search for in each element of allNames array. The two variables (allNames and searchString) are passed as argument to the findNames method when it is called.

The method findNames is defined and it accept two parameters, an array containing list of names and the name to search for.

Inside the findNames method, we initialized and assigned an ArrayList called resultName. The resultName variable is to hold list of element found that contain the searchString.

The first for-loop goes through the elements in the allNames array and compare it with the searchString. If any element is found containing the searchString; it is added to the resultName variable.

The second for-loop goes through the elements of the resultName array and output it. The output is empty if no element was found added to the resultName variable.

During comparison, the both string were converted to lower case before the comparison because same lowercase character does not equal same uppercase character. For instance 'A' is not same as 'a'.

8 0
3 years ago
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