The first term will be 3 and the sum of the first 9 terms will be 81.
<h3>What is Arithmetic progression?</h3>
The difference between every two successive terms in a sequence is the same this is known as an arithmetic progression (AP).
The arithmetic progression has wider use in mathematics for example sum of natural numbers.
Natural number = 1,2,3,4,5,6,7,8...
Given,
Six terms as 10.5
So,
a₆ = 10.5
Common difference(d) = 1.5
The nth term of an AP is given by
= a + (n-1)d
So,
a₆ = a + (6-1)d
10.5 = a + 5(1.5)
a = 3
Now,
The Sum of n terms is given by
S = n/2[2a + (n-1)d]
S = 9/2[6 + 8(1.5)]
S = 81
Hence the first term will be 3 and the sum of 9 terms will be 81.
For more about Arithmetic progression
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Answer: uhhh 54
Step-by-step explanation:
Answer:
For part 6: 39
Step-by-step explanation:
You have your starting number and then it gets added to a product of two numbers. 8 + (2x2) = 12. 12 + (2x3) = 18. 18 + (3x3) = 27. 27 + (3x4) = 39. That is the most logical answer I was able to find.
Answer:
78 dollars
Step-by-step explanation:
Function c is defined by the equation c(n) = 50 + 4n. It gives the monthly cost, in dollars, of visiting a gym as a function of the number of visits, n. Find the value of c(7).
Given:
c(n) = 50 + 4n
Where,
c = monthly cost of visiting a gym
n = number of visits
Find the value of c(7)
That is, when n = 7
c(n) = 50 + 4n
c(7) = 50 + 4(7)
= 50 + 28
= 78
c(7) = 78 dollars
Use: 0, 4, 6, 11, 9, 8, 9, 1, 5, 9, 7 to construct a box-and-whisker plot. List the maximum, minimum, and quartiles
gulaghasi [49]
Answer:
Step-by-step explanation:
<h3>Given</h3>
- 0, 4, 6, 11, 9, 8, 9, 1, 5, 9, 7
<h3>To find</h3>
- List 5 points of box and whisker plot
<h3>Solution</h3>
<u>Step 1</u>
<u>Putting the data in the order from smallest to greatest:</u>
- 0, 1, 4, 5, 6, 7, 8, 9, 9, 9, 11
<u>Step 2</u>
- The minimum and maximum = 0 and 11
- Medium quartile is the middle number ⇒ Q2 = 7
- First quartile = middle of the lower part ⇒ Q1 = 4
- Third quartile = middle of the highest part ⇒ Q3 = 9
<u>So the 5 numbers are:</u>