5 8 One third for music.
Another third for food.
One more for drinks and others. In turn, this amount
will be divided into equal parts: one for flavored water, another
for soft drinks, one more for disposable plates and glasses, and
the last one for street decorations.
What fraction of the money will be used to buy drinks? 8
You could say that the dogs weighed about 40 more pounds than the cats.
The graphs that are shown are box and whisker plots. The middle line of each plot is the median.
For the dogs, the median is 50.
For the cats, the median is 10.
If you compared the medians, you could say that the dogs are about 40 more heavier than the cats.
Answer:
17
Step-by-step explanation:
Answer:
a.
lower Quartile= 57.5
Upper Quartile=81
b.
23.5
c.
box-plot is attached in excel file
Step-by-step explanation:
The data is arranged in ascending order so, the lower quartile denoted as Q1 can be calculated as under
Q1=((n+1)/4)th score=(41/4)th score=(10.25)th score
Q1=10th score+0.25(11th-10th)score
Q1=57+0.25(59-57)=57+0.5=57.5
Q1=57.5
The data is arranged in ascending order so, the third quartile denoted as Q3 can be calculated as under
Q3=(3(n+1)/4)th score=(3*41/4)th score=(30.75)th score
Q3=30th score+0.75(31th-30th)score
Q3=81+0.75(81-81)=81+0=81
Q3=81
b)
Interquartile range=IQR=Q3-Q1=81-57.5=23.5
IQR=23.5
c)
The box-plot is made in excel and it shows no outlier. The box-plot shows the 5-number summary(minimum-Q1-median-Q3-maximum) as 25-57.5-72-81-98.
Let us assume that cost of each granola bar be $x and that of a cup of yogurt be $y
From person A's purchase, we get
12x + 7y = 15.5; equation A
And from person B's purchase,
6x + 11y = 11.5; equation B
Let us multiply equation B by 2 and subtracting equation A from it, we will get
12x + 22y - 12x - 7y = 23 - 15.5,
=> 15y = 7.5
or, y = 0.5
Substituting value of y in equation A, we can find x
12x + 7*0.5 = 15.5
=> x = (15.5 - 3.5)/12
or, x = 1
Therefore, cost of granola bar is $1, and that of yogurt is $0.5