Consider that the length of rectangle A is 10 cm and its width is 6 cm. Which rectangle is similar to rectangle A? A) A rectangl
1 answer:
ANSWER
B) A rectangle with a length of 15 cm and a width of 9 cm.
EXPLANATION
The given rectangle, A, has length, 10cm and its width is 6cm.
The rectangle that is similar to rectangle A, has the corresponding sides in the same proportion.
For option A, the triangle has length 9cm and width 6cm.
The ratio of the corresponding sides are:
Since the ratios are not equal, the two triangles are not similar.
For the triangle in option B, the length is 15cm and the width is 9cm.
The ratio of the corresponding sides are:
Since the sides of the triangle are in the same proportion, the two triangles are similar.
For option C, the proportions are not the same.
The proportions are not the same for the triangle in option D.
B) A rectangle with a length of 15 cm and a width of 9 cm.
EXPLANATION
The given rectangle, A, has length, 10cm and its width is 6cm.
The rectangle that is similar to rectangle A, has the corresponding sides in the same proportion.
For option A, the triangle has length 9cm and width 6cm.
The ratio of the corresponding sides are:
Since the ratios are not equal, the two triangles are not similar.
For the triangle in option B, the length is 15cm and the width is 9cm.
The ratio of the corresponding sides are:
Since the sides of the triangle are in the same proportion, the two triangles are similar.
For option C, the proportions are not the same.
The proportions are not the same for the triangle in option D.
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Answer:
So the p value obtained was a very low value and using the significance level given we have
so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.
Step-by-step explanation:
Data given and notation
n=115 represent the random sample taken
X=46 represent the number of people that have traded in their old car.
estimated proportion of people that have traded in their old car
is the value that we want to test
represent the significance level
Confidence=90% or 0.9
z would represent the statistic (variable of interest)
represent the p value (variable of interest)
Concepts and formulas to use
We need to conduct a hypothesis in order to test the claim that the proportion is less than 0.48.:
Null hypothesis:
Alternative hypothesis:
When we conduct a proportion test we need to use the z statistic, and the is given by:
(1)
The One-Sample Proportion Test is used to assess whether a population proportion is significantly different from a hypothesized value
.
Calculate the statistic
Since we have all the info requires we can replace in formula (1) like this:
Statistical decision
It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.
The significance level provided . The next step would be calculate the p value for this test.
Since is a left tailed test the p value would be:
So the p value obtained was a very low value and using the significance level given we have
so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 5% of significance the proportion of people that have traded in their old car is lower than 0.48 or 48%.
9514 1404 393
Answer:
4230
Step-by-step explanation:
4.23×10³ = 4.23×<u>1000</u> = <u>4230</u>
