What are the domain and range of f(x) = 4x

Use the function below to find F(2). F(t) = 2•1/2^3t

navik [9.2K]

Answer:

$F(2)= \frac{1}{32}$

Step-by-step explanation:

The given function is

$F(t) = 2 \cdot \: \frac{1}{{2}^{3t} }$

To find F(2), we substitute t=2 into the function.

This means that wherever we see t, we put 2

$F(2) = 2 \cdot \: \frac{1}{{2}^{3 \times 2} }$

We multiply the exponent in the denominator to get:

$F(2) = 2 \cdot \: \frac{1}{{2}^{6} }$

We evaluate to get:

$F(2) = 2 \cdot \: \frac{1}{64}$

We now cancel the common factors to get:

$F(2) = \frac{1}{32}$

6 0

3 years ago

How do you estimate 1,374×6

san4es73 [151]

The best estimate for 1,374 is 1,400 and the best estimate for 6 is 10. This is because anything that is 5 and above you change it. Example: 16 the best estimate for 16 is 20 because 6 is above 5. And when a number is 4 and below you change the number below. Example: 12 the best estimate for 12 is 10 because 2 is below 4. And when the number is perfect like 10, you can keep the number the same. Example:10,20,30,40,50,60etc.
Hope this Helped! :)

4 0

4 years ago

The product of two numbers

sladkih [1.3K]

Answer:

The product of two numbers is the result you get when you multiply them together. So 12 is the product of 3 and 4, 0 is the product of 4 and 5 and so on.

Step-by-step explanation:

4 0

3 years ago

Rectangle ABCD has vertices at (-7,-2); (1, -2); (1, -8); and (-7, -8) respectively. If GHJK is a similar rectangle where G(2, 5

Gennadij [26K]

Answer:

Points J and K could be located at:

J(2,2)

K(6,2)

Step-by-step explanation:

Consider the vertices have a x and y coordinate:

A: x coordinate=-7 y coordinate=-2

B: x coordinate=1 y coordinate=-2

C: x coordinate=1 y coordinate=-8

D: x coordinate=-7 y coordinate=-8

G: x coordinate=2 y coordinate=5

H: x coordinate=6 y coordinate=5

Then it is possible to calculate the distance between the x and y coordinates:

x coordinate of Vertices AB:

x coordinate of B- x coordinate of A=1-(-7)=8

The distance between A and B is 8

y coordinate of Vertices AC:

y coordinate of A- y coordinate of C=-2-(-8)=6

The distance between A and C is 6

Then we know that the side AB of Rectangle ABCD measures 8 and the side AC, measures 6.

Repeat the analysis with Rectangle GHJK. In this case, is only possible to calculate the distance with x coordinate.

x coordinate of Vertices GH:

x coordinate of H- x coordinate of G=6-(2)=4

The distance between G and H is 4

We can see that the distance in x of the Rectangle ABCD is 8, and the distance in x of the Rectangle GHJK is 4, it means that the measure of ABCD is twice GHJK.

Then, if the distance in y coordinate of Vertices AC is 6, we could say that the distance in y coordinate of Vertices GJ is 3.

Points J and K could be located at:

J(2,2)

K(6,2)

3 0

3 years ago

Please help and explain!

Scrat [10]

K is the slope of the line formed by connecting the points.
Use slope formula:
$\frac{y_2 - y_1}{x_2 - x_1}$
where the 2 points are the end points of the line (First and last going Left to right)
$(x_1,y_1) = (2,7) \\ (x_2,y_2) = (8,28)$
Substitute into slope formula
$k= \frac{28-7}{8-2} = \frac{21}{6} = \frac{7}{2}$
You can check if this is correct by going back to graph and going "up 7" and "over 2" to get from one point to the next.

5 0

3 years ago

What are the domain and range of f(x) = 4x – 8?