Answer:
If you need help, here is some tutors that can help you out!! (This is the website for them):
https://www.varsitytutors.com/en/tutoring-boston?ad_test=private-tutors-mbg-1-543&geoid=9001994&network=g&matchtype=e&keyword=tutors&creative=267098231213&device=c&devicemodel=&placement=&position=1t1&capaignid=694010146&adgroupid=35792014757&loc_physical_ms=9001994&loc_interest_ms=&keywordId=aud-346888279867:kwd-29593132&zip=02108&accountid=%7B764-479-6186%7D&gclid=Cj0KCQiAt_PuBRDcARIsAMNlBdo2XcWWplBEcBaiWkI5H6cXK-YEDOk5QsG2tKK04gE_P6YcKSFdu48aAo5-EALw_wcB
Best of luck finding one!!!
Let the required equation be y = mx + c; where y = 1, m = f'(0), x = 0
f(a) = sec(a)
f'(a) = sec(a)tan(a)
f'(0) = sec(0)tan(0) = 0
y = mx + c
1 = 0(0) + c
c = 1
Therefore, required equation is
y = 1.
Answer:
sin⁴x - sin²x
sin²x(sin²x - 1)
(1 - cos²x)(1 - cos²x - 1)
(1 - cos²x)(-cos²x)
-cos²x + cos⁴x
cos⁴x - cos²x
2.57 is the anwser. it comes out to be 2.56666667 which woukd round up to 2.57
