How can the mean be 3 1/2 people when half a person does not exist

The 7th grade class experienced a 15% decrease in enrollment. Last year, the 7th grade class had 280 students. How many students

Monica [59]

238 students are enrolled in the 7th grade class this year

<u>Solution: </u>

Given that

Percentage decrease in number of students enrolled in 7th grade = 15%

Number of students enrolled last year = 280

Need to determine number of students enrolled in 7th grade this year.

Lets assume number of students enrolled this year = x

<em>Percentage decrease in enrollment </em>= (Number of student enrolled last year – Number of students enrolled this year) whole divided by number of students enrolled last year multiplied by 100

$\begin{array}{l}{\Rightarrow 15=\frac{280-x}{280} \times 100} \\\\ {=>15 \times 280=28000-100 x} \\\\ {=>100 \mathrm{x}=28000-4200=23800} \\\\ {\Rightarrow x=\frac{23800}{100}} \\\\ {\Rightarrow x=238}\end{array}$

Hence number of students enrolled this year = 238.

7 0

3 years ago

Two groups of friends go to a movie. Each ticket costs the same amount. One group spends $57. The other group spends $95. List

kenny6666 [7]

Answer:

1) All possible number tickets for group that spends $57: A, B, C, D

2) All possible number tickets for group that spends $95: B, C, E, F

3) Each ticket will cost at most $19

Step-by-step explanation:

We are told that one group spends $57 dollars while the other group spends $95.

Now,we want to find all possible whole number ticket prices for each group and at most how much each ticket costs.

To do this, let's first find the factors of both amounts which will give us all possible whole number ticket prices for each group.

57: 1, 3, 19, 57

95: 1, 5, 19, 95

Since each ticket costs same amount, to find out at most how much each ticket costs, we will select the highest common factor of both groups which is 19.

Thus,each ticket will cost at most $19

8 0

3 years ago

I need help solving this problem |5x - 1| < 1

VashaNatasha [74]

Imagine what the graph would look like. Does it open upwards or downwards?

5x - 1 has a positive slope of 5 and it is reflected horizontally. The graph would be shaped like a V. A limited segment, or none, of the graph is below a certain value of y, and the rest outside it is above.

Hence, the solution must be a < x < b.

|5x - 1| < 1

5x - 1 < 1

x < 2/5

|5x - 1| < 1

5x - 1 > -1

x > 0

0 < x < 2/5

4 0

3 years ago

See the question below.

zheka24 [161]

your answer is B i hope this helpss

4 0

3 years ago

Read 2 more answers

I need help with this please....Thanks

IrinaK [193]

Answer:

The total cost of redecoration is £66, that is less than £75. Tenant can decorate the room for the budget set.

Step-by-step explanation:

Lets start calculating the areas of shorter and longer walls.

The area of shorter wall is

2.65m*2.98m=7.897m^2.

The area of longer wall is

3.94m*2,65m=10.441m^2.

Together the area of one long and one short wall is

7.897m^2+10.441m^2=18.338m^2.

The area to be painted ( one short and one long wall) is 18.338m^2 that is less than 30m^2, and hence only one tin of paint is needed (costs £16).

If there is assumed that the sheets of wallpaper must be whole from floor to ceiling, the calculations are following.

We get from one roll

10m/2.65m=3.77 sheets; we can use only 3 of them

The width of the walls is 3,94m+2,98m=6,92m,

and division gives 6.92m/0.52m=13,3... .

Hence it requires 14 sheets, that is 5 rolls of wallpaper.

Wallpaper costs 5*£10=£50 and altogether it is needed £50+£16=£66 to redecorate the room.

7 0

3 years ago