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3 years ago

7

Someone please help! What is the surface area of the prism? ( I have to edit the picture in)

2 answers:

Nady [450]3 years ago

8 0

Put the numbers in,I think that would help me the person down below.

ale4655 [162]3 years ago

4 0

I will help you if you want

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A given field mouse population satisfies the differential equation dp dt = 0.5p − 410 where p is the number of mice and t is the

ohaa [14]

Answer:

a) $t = 2 *ln(\frac{82}{5}) =5.595$

b) $t = 2 *ln(-\frac{820}{p_0 -820})$

c) $p_0 = 820-\frac{820}{e^6}$

Step-by-step explanation:

For this case we have the following differential equation:

$\frac{dp}{dt}=\frac{1}{2} (p-820)$

And if we rewrite the expression we got:

$\frac{dp}{p-820}= \frac{1}{2} dt$

If we integrate both sides we have:

$ln|P-820|= \frac{1}{2}t +c$

Using exponential on both sides we got:

$P= 820 + P_o e^{1/2t}$

Part a

For this case we know that p(0) = 770 so we have this:

$770 = 820 + P_o e^0$

$P_o = -50$

So then our model would be given by:

$P(t) = -50e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=-50 e^{1/2 t} +820$

$\frac{820}{50} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(\frac{82}{5}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(\frac{82}{5}) =5.595$

Part b

For this case we know that p(0) = p0 so we have this:

$p_0 = 820 + P_o e^0$

$P_o = p_0 -820$

So then our model would be given by:

$P(t) = (p_o -820)e^{1/2t} +820$

And if we want to find at which time the population would be extinct we have:

$0=(p_o -820)e^{1/2 t} +820$

$-\frac{820}{p_0 -820} = e^{1/2 t}$

Using natural log on both sides we got:

$ln(-\frac{820}{p_0 -820}) = \frac{1}{2}t$

And solving for t we got:

$t = 2 *ln(-\frac{820}{p_0 -820})$

Part c

For this case we want to find the initial population if we know that the population become extinct in 1 year = 12 months. Using the equation founded on part b we got:

$12 = 2 *ln(\frac{820}{820-p_0})$

$6 = ln (\frac{820}{820-p_0})$

Using exponentials we got:

$e^6 = \frac{820}{820-p_0}$

$(820-p_0) e^6 = 820$

$820-p_0 = \frac{820}{e^6}$

$p_0 = 820-\frac{820}{e^6}$

8 0

3 years ago

Ok so if -4/5 is divided by 2 what would be the quotient

scoray [572]

<h2>-2/5</h2>

$-\frac{4}{5}\div \:2$

$-\frac{4}{5}\div \frac{2}{1}$

$-\frac{4}{5}\times \frac{1}{2}$

$-\frac{4}{10}=-\frac{2}{5}$

3 0

3 years ago

Read 2 more answers

Billy is 5 2/3 feet tall. Maris is 4 11/12 feet tall. How much taller is billy

3241004551 [841]

3/4 feet

You can set this up as an equation and solve

$5\frac{2}{3}-4\frac{11}{12} =5\frac{8}{12} -4\frac{11}{12} =4\frac{20}{12} -4\frac{11}{12}=\frac{9}{12} =\frac{3}{4}$

3 0

3 years ago

Plzz answer I don't understand

nadezda [96]

Height is 18 for question 3.

4 0

4 years ago

A cylinder has a radius of 5 feet and a height of 8 feet. Which of the following can be used to calculate the volume of a cone t

Cloud [144]

The formula is pi*r^2*h/3
your answer would have to be B

7 0

3 years ago