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Hoochie [10]
3 years ago
15

It costs $70 for 50 tickets. How much does each ticket cost?

Mathematics
2 answers:
BigorU [14]3 years ago
6 0
If you do $70 divided by 50, you would get 1.4, and 1.4 times 50 would be $70. So, each ticket would cost $1.40.
liberstina [14]3 years ago
5 0
1 dollar and 40 cents
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Now there is a square city of unknown size with a gate at the center of each side. There is a tree 20 b from the north gate. Tha
Brums [2.3K]

Answer:

The length of each side of the city is 250b

Step-by-step explanation:

Given

a = 20 --- tree distance from north gate

b =14 --- movement from south gate

c = 1775 --- movement in west direction from (b)

See attachment for illustration

Required

Find x

To do this, we have:

\triangle ADE \sim \triangle ACB --- similar triangles

So, we have the following equivalent ratios

AE:DE = AB:CB

Where:

AE = 20\\ DE = x/2 \\ AB = 20 + x + 14 \\ CB = 1775

Substitute these in the above equation

20:x/2 = 20 + x + 14: 1775

20:x/2 = x + 34: 1775

Express as fraction

\frac{20}{x/2} = \frac{x + 34}{1775}

\frac{40}{x} = \frac{x + 34}{1775}

Cross multiply

x *(x + 34) = 1775 * 40

Open bracket

x^2 + 34x = 71000

Rewrite as:

x^2 + 34x - 71000 = 0

Expand

x^2 + 284x -250x - 71000 = 0

Factorize

x(x + 284) -250(x + 284)= 0

Factor out x + 284

(x - 250)(x + 284)= 0

Split

x - 250 = 0 \ or\ x + 284= 0

Solve for x

x = 250 \ or\ x =- 284

x can't be negative;

So:

x = 250

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Answer:

Step-by-step explanation:

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h²  + (w² - 1)² = (w² + 1)²

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{Compare with (a + b)² - (a -b)² = 4ab where a =w² & b = 1}

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                   h=\sqrt{4w^{2}} = \sqrt{2*2*w*w} \\\\\\h = 2w

b) Area of triangle = \frac{1}{2}b*h

                               =\dfrac{1}{2}*(w^{2}-1) *2w\\\\= (w^{2}-1)*w = w^{2}*w - 1*w\\\\=w^{3}-w

c) w =2

Area of triangle = 3w = 3*2 = 6

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1/1000 of a liter is a milliliter, so a.
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10 1/2 is the answer.

Steps:
Change the fraction to improper fractions.
Multiply
Reduce
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Steps(Another Way):
Change the fraction to improper fractions.
Reduce by crossing it(5 and 15 reduced to 1 and 3; 4 and 14 reduced to 2 and 7.)
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