T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
10. 5c+4c+c=5+4+1 you get one because when have a unsolved variable it is automaticlly 1. so it solves out to be 5x1+4x1+1=10.
Answer:
I think it is x-2 and x=8
Hope it helps
The answer is D 10.5 miles per hour
Answer:
The answer is -21
Step-by-step explanation:
To find the answer just multiply 7 by 3 and that's 21, so just add a negative sign to 21 and you get -21. I hope this helps :) please give me brainliest :)