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3 years ago

Please help me with this question???????????????????????????

Mathematics

1 answer:

asambeis [7]3 years ago

6 0

The answer would be y=-11x-48

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Find the slope -3/5 3/5 5/3 -5/3

Monica [59]

The slope is y=-5/3x+2

8 0

2 years ago

Rosalie earns extra money by working as a babysitter over the weekend. She charges $10 to drive to the home and an additional $8

agasfer [191]

Answer: The input values are B-number of hours (x).

The output values are C-charge for babysitting(y).

The value of $10 represents the B-y intercept.

The value of $8 represents the C-slope.

Step-by-step explanation:

Charges to drive to the home= $10

Additional charges per hour=$8

Let x be the hour she worked (independent variable) and y be the total charge for baby sitting (dependent variable)

Thus, the input values are number of hours (x) and the output values are charge for babysitting(y)

According to the situation the equation would be

y=8x+10

which is equivalent to the slope intercept form y=mx+c, where

m=8, slope of line

At x=0, y=10

Thus, $10 represents the y intercept

6 0

3 years ago

Read 2 more answers

Pls pls pls help!!!!

pav-90 [236]

Answer: I think A 1,220 (I'm not sure)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Mike just hopped on the edge of a merry-go-round. What are his linear and angular speeds if the diameter of the merry-go-round i

dsp73

Step-by-step explanation:

Given that,

The diameter of the merry-go-round, d = 14 feet

Time taken, t = 6 seconds

Radius, r = 7 feet

The linear speed of the merry-go-round is given by :

$v=\dfrac{2\pi r}{t}\\\\v=\dfrac{2\pi \times 7}{6}\\\\=7.33\ m/s$

Also,

$v=r\omega$

Where

$\omega$ is the angular speed

So,

$\omega=\dfrac{v}{r}\\\\\omega=\dfrac{7.33}{7}\\\\=1.04\ rad/s$

Hence, his linear and angular speeds are 7.33 m/s and 1.04 rad/s.

8 0

3 years ago

I need help please

IRISSAK [1]

Answer:

2,3,6,7 from the top

Step-by-step explanation:

5 0

3 years ago