The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
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The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
Read more about rotation at:
brainly.com/question/4289712
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Answer:
X =0
Step-by-step explanation:
divide each term by 15 and simp
Answer:
in the intersection region of all the solution in the system.
X/58.65 = 15/100
(58.65*15)/100 = tip
0 and 2
f(x) = g(x) will be the input or x value at which f and g have the same output or y value. Look in the table where two numbers repeat right next to each other.
−1 −7/2 −9/2
0 −3 −3
1 −2 −3/2
2 0 0
3 4 3/2
4 12 3
5 28 9/2
There are two solutions to f(x) = g(x) which are x=0 and x=2.
