Johnny is selling tickets to a school play. On the first day of ticket sales he sold 14 senior (S) citizen tickets and 4 child (C) tickets for a total of $200. On the second day of ticket sales he sold 7 senior (S) citizen tickets and 1 child (C) ticket for a total of $92. What is the price of one child ticket?
14S + 4C = 200
14S = 200 - 4C
S = (200 - 4C)/14
7S + 1C = 92
7S = 92 - C
S = (92 - C)/7
(200 - 4C)/14 = (92 - C)/7
7 x (200 - 4C) = 14 x (92 - C)
1400 - 28C = 1288 - 14C
1400 - 1288 = 28C - 14C
112 = 14C
C = 112/14 = 8
the price of one child ticket = $8
Answer: look at the ss :))
Step-by-step explanation:
13/4 =12/4 +1/4=3+1/4 so it has to be between 3 and 4 on the number line.Hope this helps and thank you for letting me help you ✅
The answer is D
if the legs are 5 and 4 cm the equation to find the hypotenuse would be 5^2+4^2=c^c
5 squared is 25 and 4 squared is 16 that gives you 41, normally you would square root the 41 but it gives you a decimal number
