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astraxan [27]
3 years ago
10

Need help with naming this angle

Mathematics
1 answer:
Helga [31]3 years ago
4 0

Answer:

alternate exterior angle

Step-by-step explanation:

the angles are on the opposite side and on the exterior of the transversal. One is on the top side of the exterior and the twelve is on the bottom side of the exterior so thats why its an exterior angle. The reason why it is alternate is because its on opposite sides of the lines

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Assume that 7 is a. We already know that c = 25. The equation is c^2 - a^2 = b^2.
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2 years ago
Can somebody help me ??
fiasKO [112]

Answer: C

Step-by-step explanation:

Formula: V=\pi r^2h

We do not have the radius, but we do have the diameter. A diameter is twice the radius, therefore we can divide the diameter by 2 in order to obtain the radius.

\frac{d}{2}=\frac{12}{2}  =6

Plug this info into the formula.

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4 0
2 years ago
A metallurgist has one alloy containing 32% copper and another containing 65% copper. How many pounds of each alloy must he use
kompoz [17]

Answer:

<h2>30.67 pounds of 32% copper alloy and 10.33 pounds of 65% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 32% copper and the second alloy contains 65% alloy.

We wish to make 44 pounds of a third alloy containing 42% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 44\text{ }pounds=x+y        -(i)

      Total weight of copper = 42\%\text{ of 44 pounds = }32\%\text{ of }x\text{ pounds + }65\%\text{ of }y\text{ pounds }

       \dfrac{42\times 44}{100}=\dfrac{32x}{100}+\dfrac{65y}{100}\\\\ 32x+65y=1848        -(ii)

       Subtracting 32 times first equation from second equation,

32x+65y-32x-32y=1848-32\times44\\33y=440\\y=13.333\text{ }pounds \\x=30.667\text{ }pounds

∴ 30.67 pounds of first alloy and 13.33 pounds of second alloy were used.

4 0
2 years ago
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