Question

The width of a rectangle is represented by 5 + 2y. The length is twice as long as the width. What is the perimeter of the rectangle? Give all correct answers

Answer 1

The answer is 12y+30.
Twice the width would be 10+4y, so the length is 10+4y.
To find the perimeter, we can do 2(5+2y) + 2(10+4y).
That equals 10+4y+20+8y.
Which, equals 12y+30.