Let x = angle we must find
tan x = 14/30
arctan(tan x) = arctan(14/30)
x = 25.0168934781
Answer: 25 degrees
Answer:
Step-by-step explanation:
Geometric sequence
Each term in a geometric sequence can be computed as the previous term by a constant number called the common ratio. The formula to get the term n is
where is the first term of the sequence
The problem describes Georgie took 275 mg of the medicine for her cold in the first hour and that in each subsequent hour, the amount of medicine in her body is 91% (0.91) of the amount from the previous hour. It can be written as
amount in hour n = amount in hour n-1 * 0.91
a)
This information provides the necessary data to write the general term as
b)
In the 8th hour (n=8), the remaining medicine present is Georgie's body is
Answer:
Hope this helps 0>0
Step-by-step explanation:
Let x represent the number of sales each man had.
For Salesman A, he earns $65 per sale; this is 65x.
For Salesman B, he earns $40 per sale; this is 40x. We also add to this his weekly salary of $300; this gives us 40x+300.
Since their pay was equal, set the two expressions equal:
65x = 40x+300
Subtract 40x from each side:
65x-40x = 40x+300-40x
25x = 300
Divide both sides by 25:
25x/25 = 300/25
x = 12
Answer:
See below
Step-by-step explanation:
Given function is ,
=> f(x) = 4x + 7.
Replace f(x) with y ,
=> y = 4x + 7
For finding the inverse , interchange x and y ,
=> x = 4y + 7
Now solve for y ,
=> 4y = x - 7
=> y = x-7/4
Replace y with f-¹(x) ,
=> f-¹(x) = (x-7)/4
These are the required steps .
Answer: see proof below
<u>Step-by-step explanation:</u>
Given: A + B + C = π → C = π - (A + B)
→ sin C = sin(π - (A + B)) cos C = sin(π - (A + B))
→ sin C = sin (A + B) cos C = - cos(A + B)
Use the following Sum to Product Identity:
sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]
cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]
Use the following Double Angle Identity:
sin 2A = 2 sin A · cos A
<u>Proof LHS → RHS</u>
LHS: (sin 2A + sin 2B) + sin 2C
LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C