Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Answer:
8 x 6 = 48
48 divided by 2 = 24
24 x 2 = 48
10 x 12 = 120
120 x 2 = 240
8 x 12 = 96
Add all given areas:
48 + 96 + 240 = 384 in2 is your answer.
Answer:
2/7
Step-by-step explanation:
You do the number it goes up, 1 to 3 in this case, over the number it goes sideways, 3 to -4. My teacher always said rise over run to help us remember.
here's the solution,
- n = 11
- a = 5 ( a = first term )
- d = 6 ( d = common difference )
we know,
=》
=》
=》
=》
=》
nth term ( 11th term ) = 65
Answer:
Step-by-step explanation:
The question isn't clear...
