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vladimir1956 [14]
3 years ago
15

Help me with this please

Mathematics
1 answer:
snow_lady [41]3 years ago
8 0

jefferey read 1/5 the pages of Toby

 so you would divide the pages Toby read by 5, which is the same as t/5

the first one is the correct answer

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9. Aaron has a lemonade business. If he sells each glass of lemonade for $2.75, and he sold 11
marin [14]

Answer:

$27.75

Step-by-step explanation:

Multiply $2.25 by 11 to get the answer

4 0
3 years ago
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73.085 in standard form
jeka57 [31]

Eres una pinche pendejha huevona

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7 0
3 years ago
For what value of constant c is the function k(x) continuous at x = 0 if k =
nlexa [21]

The value of constant c for which the function k(x) is continuous is zero.

<h3>What is the limit of a function?</h3>

The limit of a function at a point k in its field is the value that the function approaches as its parameter approaches k.

To determine the value of constant c for which the function of k(x)  is continuous, we take the limit of the parameter as follows:

\mathbf{ \lim_{x \to 0^-} k(x) =  \lim_{x \to 0^+} k(x) =  0 }

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= c }

Provided that:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}= \dfrac{0}{0} \ (form) }

Using l'Hospital's rule:

\mathbf{\implies  \lim_{x \to 0} \ \  \dfrac{\dfrac{d}{dx}(sec \ x - 1)}{\dfrac{d}{dx}(x)}=  \lim_{x \to 0}   sec \ x  \ tan \ x = 0}

Therefore:

\mathbf{\implies  \lim_{x \to 0 } \ \  \dfrac{sec \ x - 1}{x}=0 }

Hence; c = 0

Learn more about the limit of a function x here:

brainly.com/question/8131777

#SPJ1

5 0
2 years ago
A DVD player that normally cost $160 is on sale for 70% of its normal price.What is the sale price of the DVD player.
maw [93]
160 $ = 100%
     x $ = 70%


100 x = 11200
     x =  112


160,00 - 112,00 =  48,00$


7 0
3 years ago
Caroline flips a coin 3 times. According to the tree diagram, how many possible outcomes exist?
wariber [46]
I believe the answer is D.8
3 0
3 years ago
Read 2 more answers
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