All but the last one I think but don't quote me
Answer:
111 / 190
Step-by-step explanation:
Let us first compute the probability of picking 2 of each sweet. Take liquorice as the first example. There are 12 / 20 liquorice now, but after picking 1 there will be 11 / 19 left. Thus the probability of getting two liquorice is demonstrated below;

Apply this same concept to each of the other sweets;

Now add these probabilities together to work out the probability of drawing 2 of the same sweets, and subtract this from 1 to get the probability of not drawing 2 of the same sweets;

The probability that the two sweets will not be the same type of sweet =
111 / 190
342/18 18 x 10= 180 342 - 180= 162 18 x 9= 90 + 72= 162 10+9= 19 The answer is 19
Answer: 3/2
Step-by-step explanation:
<u>Given</u>
6/10 + 9/10
<u>Add the numerator together</u>
= (6 + 9) / 10
<u>Simplify by addition</u>
= 15 / 10
<u>Simplify to simplest form by division</u>
= (15 ÷ 5) / (10 ÷ 5)
= 3 / 2
Hope this helps!! :)
Please let me know if you have any questions