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1 year ago

15

Write 80 as the product of its prime factors

1 answer:

ehidna [41]1 year ago

7 0

Answer:

2 * 2 * 2 * 2 * 5.

Step-by-step explanation:

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WILL MARK BRANLIEst

LenaWriter [7]

Answer:

click on the thanks button

5 0

2 years ago

HELPPP PLEASEEEEEEEEE

Mashutka [201]

For synthetic division:
1) Write the coefficients of the polynomial under the division symbol, in order. Make sure you include coefficients that are 0, so they may not be written out in the polynomial!
The coefficients are 7, 1, 0 (the coefficient of x), and -4 in that order

2) The divisor is in the form of x - a. The number "a" goes outside the bracket.
a = 5

Since 7, 1, 0, -4 are under the bracket and 5 is outside the bracket, the answer is C.

------

Answer: C

7 0

2 years ago

Find a cubic function with the given zeros.

Fed [463]

Answer:

The correct option is D) $f(x) = x^3 + 2x^2 - 2x - 4$ .

Step-by-step explanation:

Consider the provided cubic function.

We need to find the equation having zeros: Square root of two, negative Square root of two, and -2.

A "zero" of a given function is an input value that produces an output of 0.

Substitute the value of zeros in the provided options to check.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x + 4$ .

$f(x) = x^3 + 2x^2 - 2x + 4\\f(x) = (-2)^3 + 2(-2)^2 - 2(-2) + 4\\f(x) =-8 + 2(4)+4 + 4\\f(x) =8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 + 2x - 4$ .

$f(x) = x^3 + 2x^2 + 2x - 4\\f(x) = (-2)^3 + 2(-2)^2 + 2(-2) - 4\\f(x) =-8+2(4)-4-4\\f(x) =-8$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 - 2x^2 - 2x - 4$ .

$f(x) = x^3 - 2x^2 - 2x - 4\\f(x) = (-2)^3 - 2(-2)^2 - 2(-2) - 4\\f(x) =-8-8+4-4\\f(x) =-16$

Therefore, the option is incorrect.

Substitute x=-2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-2)^3+2(-2)^2 - 2(-2) - 4\\f(x) =-8+8+4-4\\f(x) =0$

Now check for other roots as well.

Substitute x=√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (\sqrt{2})^3+2(\sqrt{2})^2 - 2(\sqrt{2}) - 4\\f(x) =2\sqrt{2}+4-2\sqrt{2}-4\\f(x) =0$

Substitute x=-√2 in $f(x) = x^3 + 2x^2 - 2x - 4$ .

$f(x) = x^3 + 2x^2 - 2x - 4\\f(x) = (-\sqrt{2})^3+2(-\sqrt{2})^2 - 2(-\sqrt{2}) - 4\\f(x) =-2\sqrt{2}+4+2\sqrt{2}-4\\f(x) =0$

Therefore, the option is correct.

8 0

2 years ago

What is the simplest form of 3/6

poizon [28]

The simplest form of 3/6 is 1/2 because 3 is half of 6

3 0

2 years ago

Read 2 more answers

Ashley wants to pour 15.82 grams of salt into a container. So far, she has poured 13.87 grams. How much more salt should Ashley

erik [133]

Answer:

1.95

Step-by-step explanation:

Basically, you subtract: 5.82 - 13.87 = 1.95

Then, see: 15.82 - 1.950 = 13.87

Then you have your answer :D

Ashley has to pour 1.95 more grams of salt.

Brainliest, please??? :>

3 0

1 year ago

Read 2 more answers