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3 years ago

PLZ HELP ME ASAP :]]]]]

Mathematics

2 answers:

Pavel [41]3 years ago

8 0

3 there I no way he needs more than 4 cups cause there is not 6 dozens

LenKa [72]3 years ago

6 0

Answer: 3

Step-by-step explanation:

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Below are the data collected from two random samples of 500 American students on the number of hours they spend in school per da

balu736 [363]

Answer: Tara thinks correctly.

Step-by-step explanation:

Let's calculate the average value in sample A:

(4 × 70 + 5 × 100 + 6 × 125 + 7 × 135 + 8 × 70) ÷ 500 = 6,07 ≈ 6 hours

Let's calculate the average value in sample B:

(4 × 80 + 5 × 90 + 6 × 120 + 7 × 125 + 8 × 85) ÷ 500 = 6,09 ≈ 6 hours

So, Tara is correct in saying that the mean is 6.

3 0

3 years ago

Will mark brainliest

Anna007 [38]

Answer: $x\leq 3$

PLEASE MARK ME BRAINLIEST

Step-by-step explanation:

1) Simplify both sides of the inequality:

$4x+8\geq 5x+5$

2) Subtract $5x$ from both sides:

$4x+8-5x\geq 5x+5-5x$

3) Simplify:

$-x+8\geq 5$

4) Subtract $8$ from both sides:

$-x+8-8\geq 5-8$

5) Simplify:

$-x\geq -3$

6) Divide both sides by $-1$ :

$\frac{-x}{-1} =\frac{-3}{-1}$

7) Simplify:

$x\leq -3$

5 0

2 years ago

Read 2 more answers

Bring the fraction a/a−4 to a denominator of 16−a^2 really do appreciate this thx

RSB [31]

Answer:

-a(a+4)/(16 - a²)

Step-by-step explanation:

a/(a - 4) Multiply by (a + 4)/(a + 4)

= a(a + 4)/[(a – 4)(a + 4)] Multiply the denominatorator terms

= a(a + 4)/(a² - 16) Multiply by -1/(-1)

= -a(a+4)/(-a² + 16) Reorder terms in denominator

= -a(a+4)/(16 - a²)

5 0

3 years ago

Find the 76th term of the arithmetic sequences 16 14 12

grigory [225]

Answer:

a₇₆ = - 134

Step-by-step explanation:

The n th term of an arithmetic sequence is

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 16 and d = a₂ - a₁ = 14 - 16 = - 2, then

a₇₆ = 16 + (75 × - 2) = 16 - 150 = - 134

7 0

3 years ago

Please Help! This is a trigonometry question.

liraira [26]

$\large\begin{array}{l} \textsf{From the picture, we get}\\\\ \mathsf{tan\,\theta=\dfrac{2}{3}}\\\\ \mathsf{\dfrac{sin\,\theta}{cos\,\theta}=\dfrac{2}{3}}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\qquad\mathsf{(i)} \end{array}$

$\large\begin{array}{l} \textsf{Square both sides of \mathsf{(i)} above:}\\\\ \mathsf{(3\,sin\,\theta)^2=(2\,cos\,\theta)^2}\\\\ \mathsf{9\,sin^2\,\theta=4\,cos^2\,\theta}\qquad\quad\textsf{(but }\mathsf{cos^2\theta=1-sin^2\,\theta}\textsf{)}\\\\ \mathsf{9\,sin^2\,\theta=4\cdot (1-sin^2\,\theta)}\\\\ \mathsf{9\,sin^2\,\theta=4-4\,sin^2\,\theta}\\\\ \mathsf{9\,sin^2\,\theta+4\,sin^2\,\theta=4} \end{array}$

$\large\begin{array}{l} \mathsf{13\,sin^2\,\theta=4}\\\\ \mathsf{sin^2\,\theta=\dfrac{4}{13}}\\\\ \mathsf{sin\,\theta=\sqrt{\dfrac{4}{13}}}\\\\ \textsf{(we must take the positive square root, because }\theta \textsf{ is an}\\\textsf{acute angle, so its sine is positive)}\\\\ \mathsf{sin\,\theta=\dfrac{2}{\sqrt{13}}} \end{array}$

________

$\large\begin{array}{l} \textsf{From (i), we find the value of }\mathsf{cos\,\theta:}\\\\ \mathsf{3\,sin\,\theta=2\,cos\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{2}\,sin\,\theta}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\diagup\!\!\!\! 2}\cdot \dfrac{\diagup\!\!\!\! 2}{\sqrt{13}}}\\\\ \mathsf{cos\,\theta=\dfrac{3}{\sqrt{13}}}\\\\ \end{array}$

________

$\large\begin{array}{l} \textsf{Since sine and cosecant functions are reciprocal, we have}\\\\ \mathsf{sin\,2\theta\cdot csc\,2\theta=1}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{sin\,2\theta}\qquad\quad\textsf{(but }}\mathsf{sin\,2\theta=2\,sin\,\theta\,cos\,\theta}\textsf{)}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\,sin\,\theta\,cos\,\theta}}\\\\ \mathsf{csc\,2\theta=\dfrac{1}{2\cdot \frac{2}{\sqrt{13}}\cdot \frac{3}{\sqrt{13}}}} \end{array}$

$\large\begin{array}{l} \mathsf{csc\,2\theta=\dfrac{~~~~1~~~~}{\frac{2\cdot 2\cdot 3}{(\sqrt{13})^2}}}\\\\ \mathsf{csc\,2\theta=\dfrac{~~1~~}{\frac{12}{13}}}\\\\ \boxed{\begin{array}{c}\mathsf{csc\,2\theta=\dfrac{13}{12}} \end{array}}\qquad\checkmark \end{array}$

If you're having problems understanding this answer, try seeing it through your browser: brainly.com/question/2150237

$\large\textsf{I hope it helps.}$

Tags: trigonometry trig function cosecant csc double angle identity geometry

8 0

4 years ago