2 and the 4 needs to add subtract too much
Add up all of the side lengths and you get 148.4 as the perimeter.
subtract that from 150 and you're left with 1.6 m left of tape
You need to find "two-fifths of 30." Of here means multiplication:
![\begin{aligned}\dfrac{2}{5}\cdot 30 &= \dfrac{2}{5}\cdot\dfrac{30}{1}\\[0.5em] &= \dfrac{60}{5}\\[0.5em] &= 12\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%2030%20%26%3D%20%5Cdfrac%7B2%7D%7B5%7D%5Ccdot%5Cdfrac%7B30%7D%7B1%7D%5C%5C%5B0.5em%5D%20%26%3D%20%5Cdfrac%7B60%7D%7B5%7D%5C%5C%5B0.5em%5D%20%26%3D%2012%5Cend%7Baligned%7D)
There are 12 athletes in the club.
Studio = 7 yards by 4 yards
Area = 7*4 = 28 square yards.
Area of square carpet = 1 yard * 1 yard = 1 square yard
Number needed = Area of studio / Area of square carpet = 28 / 1 = 28
Number needed = 28