Answer:
1. 
2. ![x=\pm7i[tex]3.[tex]\pm 12x =a](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fp%3E%3Cp%3E3.%5Btex%5D%5Cpm%2012x%20%3Da)
4. 22
Step-by-step explanation:
1. 



2. 


![x=\pm7i[tex]3. Area of square = [tex]a^{2}](https://tex.z-dn.net/?f=x%3D%5Cpm7i%5Btex%5D%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3E3.%20Area%20of%20square%20%3D%20%5Btex%5Da%5E%7B2%7D)
Where a is the side
We are given an area o square = 
So, 


4. We are given that the solution of quadratic equation -9 and 9
So, equation becomes:


So, in the given equation 
z should be the number from which if we subtract 103 so we get 81
Substitute z = 22



Thus the value of z is 22
Intersecting point 4,2 with slope of 1/2
Answer:
a 10000
b 1000
c 100
this is the correct answer
Length- 19,19
Width- 14,14
I’m not so sure but I think that right
In the isosceles trapezoid ABCD, draw two perpendiculars AM and BL from A and B to the side CD.
Now, LM = BA = 5 m
CD = CL + LM + MD
= CL + 5 + CL (CL = MD)
= 2CL + 5
But, CD = 11
Therefore, 2CL + 5 = 11
2CL = 11 - 5
= 6
CL = 6/2 = 3m
MD = 3m
Now, consider the right triangle AMD.
We have,

= 
= 16 - 9
= 7
Hence, height of the isosceles trapezoid = AM = 