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sergiy2304 [10]
3 years ago
5

In 2009, the world's largest pumpkin weighed 784 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2009 world-record p

umpkin weighs _____ kilograms more than an average-sized pumpkin. Please provide the solution below.
Mathematics
1 answer:
denpristay [2]3 years ago
5 0
First you need to convert grams into kilograms. You know that 1kg=1000g
if 1kg=................. 1000g
   x kg=.................5000g

x=5000/1000 = 5kg
Now you need to find the difference between an average-sized pumpkin and the <span>world's largest pumpkin which is:
784-5=779

So the right answer is 779.</span>
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Answer:

63.9

Step-by-step explanation:

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3 years ago
Simplify (-8z+4) + (7z-7)
Karo-lina-s [1.5K]

Answer:

1. -1z-3

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vampirchik [111]
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3 years ago
Consider a TV set that consumes 120 W of electric power when it is on, and is kept on for an average of 6 h per day. For a unit
Andru [333]

The cost of electricity consumed by the TV per month is <u>$4.968</u>.

In the question, we are given that a TV set consumes 120W of electric power when switched on. It is kept on for a daily average of 6 hours per day. The number of days in the month is given to be 30 days. The cost per unit of electricity is 23 cents per kWh.

We are asked to find the cost of electricity the TV consumes in the month.

The daily energy consumed by the TV = Power*Daily time = 120*6 Wh = 720 Wh.

The monthly energy consumed by the TV = Daily energy*Number of days in the month = 720*30 Wh = 21600 Wh = 21600/1000 kWh = 21.6 kWh.

Hence, the total cost of electricity the TV consumes = Monthly energy*Per unit cost = 21.6*23 cents = 496.8 cents = $496.8/100 = $4.968.

Therefore, the cost of electricity consumed by the TV per month is <u>$4.968</u>.

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3 0
2 years ago
Can anyone please solve this quickly?
cricket20 [7]

Answer:

c = 10

Step-by-step explanation:

3 is to 6 as 5 is to c:

 3       5

----- = -----

  6       c

Then 3c = 30, and c = 10

8 0
3 years ago
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