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sergiy2304 [10]
2 years ago
5

In 2009, the world's largest pumpkin weighed 784 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2009 world-record p

umpkin weighs _____ kilograms more than an average-sized pumpkin. Please provide the solution below.
Mathematics
1 answer:
denpristay [2]2 years ago
5 0
First you need to convert grams into kilograms. You know that 1kg=1000g
if 1kg=................. 1000g
   x kg=.................5000g

x=5000/1000 = 5kg
Now you need to find the difference between an average-sized pumpkin and the <span>world's largest pumpkin which is:
784-5=779

So the right answer is 779.</span>
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And then you multiply it by 10,000 or you can say 10^5

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\frac{231818/2}{100000/2}

And now this equals:

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