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sergiy2304 [10]
3 years ago
5

In 2009, the world's largest pumpkin weighed 784 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2009 world-record p

umpkin weighs _____ kilograms more than an average-sized pumpkin. Please provide the solution below.
Mathematics
1 answer:
denpristay [2]3 years ago
5 0
First you need to convert grams into kilograms. You know that 1kg=1000g
if 1kg=................. 1000g
   x kg=.................5000g

x=5000/1000 = 5kg
Now you need to find the difference between an average-sized pumpkin and the <span>world's largest pumpkin which is:
784-5=779

So the right answer is 779.</span>
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Answer:

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The p value can be calculated from the alternative hypothesis with this probability:

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And the best option for this case would be:

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Step-by-step explanation:

Information provided

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X_{2}=1415 represent the number of smokers from the sample in 2010

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p_{1}=\frac{1642}{4276}=0.384 represent the proportion of smokers from the sample in 1995

p_{2}=\frac{1415}{3908}=0.362 represent the proportion of smokers from the sample in 2010

\hat p represent the pooled estimate of p

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p_v represent the value for the pvalue

System of hypothesis

We want to test the equality of the proportion of smokers and the system of hypothesis are:    

Null hypothesis:p_{1} = p_{2}    

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The statistic is given by:

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)  

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{1642+1415}{4276+3908}=0.374  

Replacing the info given we got:

z=\frac{0.384-0.362}{\sqrt{0.374(1-0.374)(\frac{1}{4276}+\frac{1}{3908})}}=2.055    

The p value can be calculated from the alternative hypothesis with this probability:

p_v =2*P(Z>2.055)=0.0399    

And the best option for this case would be:

C. between 0.01 and 0.05.

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