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sergiy2304 [10]
3 years ago
5

In 2009, the world's largest pumpkin weighed 784 kilograms. An average-sized pumpkin weighs 5,000 grams. The 2009 world-record p

umpkin weighs _____ kilograms more than an average-sized pumpkin. Please provide the solution below.
Mathematics
1 answer:
denpristay [2]3 years ago
5 0
First you need to convert grams into kilograms. You know that 1kg=1000g
if 1kg=................. 1000g
   x kg=.................5000g

x=5000/1000 = 5kg
Now you need to find the difference between an average-sized pumpkin and the <span>world's largest pumpkin which is:
784-5=779

So the right answer is 779.</span>
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Miley is trying to solve the following riddle the sum of three consecutive integers is 84 what are the integers
oee [108]

Answer:

Three consecutive numbers are 27,28,29

Step-by-step explanation:

Given :  The sum of three consecutive integers is 84.

To find : What are the integers?

Solution : Let three consecutive numbers x, x+1, x+2

So, according to given situation 'sum of three consecutive integers is 84'.

x+x+1+x+2=84

\Rightarrow 3x+3=84

\Rightarrow 3x=84-3=81

\Rightarrow x=\frac{81}{3}

\Rightarrow x=27

So,x=27

x+1= 27+1=28

x+2=27+2=29

Therefore, three consecutive numbers are 27,28,29

4 0
3 years ago
Solve this please show your work &lt;3
Nookie1986 [14]

Given:

The expression is

\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=

To find:

The simplified form of the expression.

Solution:

We have,

\sqrt[3]{48}=\sqrt[3]{8\cdot \_\_}=

The expression \sqrt[3]{48} can be written as

\sqrt[3]{48}=\sqrt[3]{8\cdot 6}

\sqrt[3]{48}=\sqrt[3]{8}\cdot \sqrt[3]{6}       [\because \sqrt[3]{ab}=\sqrt[3]{a}\sqrt[3]{b}]

\sqrt[3]{48}=2\cdot \sqrt[3]{6}

\sqrt[3]{48}=2\sqrt[3]{6}

Therefore, \sqrt[3]{48}=\sqrt[3]{8\cdot 6}=2\sqrt[3]{6}.

5 0
3 years ago
What is the solution set of the following equation? 6x^2 = 13x + 5
fiasKO [112]

Answer:

2nd

Step-by-step explanation:

using the quadric formula

- ( - 13) +  -  \sqrt{( - 3) {}^{2} - 4 \times 6( - 5) }   \div 2 \times 6

do the math and you get the second one.

{-1/3,5/2}

6 0
4 years ago
A team won 6 hockey matches and lost 9 matches. what per cent of the matches did the team win​
Mama L [17]

Answer:

66.67%

Step-by-step explanation:

total matches = 9

matches won = 6

percentage = matches won*100/ total matches

percentage = 600/9

= 66.67%

7 0
3 years ago
Read 2 more answers
-2=3(y-2) how do you solve this problem for y​
Ksivusya [100]

Answer:

y= 4/3

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−2=3(y−2)

−2=(3)(y)+(3)(−2)(Distribute)

−2=3y+−6

−2=3y−6

Step 2: Flip the equation.

3y−6=−2

Step 3: Add 6 to both sides.

3y−6+6=−2+6

3y=4

Step 4: Divide both sides by 3.

3y /3 = 4 /3

y= 4/3

Answer:

y= 4/3

8 0
3 years ago
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