1.6 is let's say one pie and 6/10 of a pie and that's how much a baker made which is obviously more that 1 pie and 3/10 of a pie that the baker made.
A process for that is
1.6 =1 6/10 = 16/10 and if u cross multiply that by
1.3 = 1 3/10= 13/10 the value in the 16/10 side will be 160 which is more that the value on the 13/10 side which is 130
Answer:
1
Step-by-step explanation:
S = {,10,11,12,13,14,15,16,17,18,19,}
n(s) = 10
P(a) = n(a) / n(s)
= 10 / 10
= 1 / 1
= 1
<em>hope this helps.....</em>
Using probability concepts, it is found that:
a)
probability of drawing a card below a 6.
b)
odds of drawing a card below a 6.
c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
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- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
Item a:
- In a standard deck, there are 52 cards.
- There are 4 types of cards, each numbered 1 to 13. Thus,
are less than 6.
Then:

probability of drawing a card below a 6.
Item b:
- Converting from probability to odd, it is:

odds of drawing a card below a 6.
Item c:
- The law of large numbers states that with a <u>large number of trials, the percentage of each outcome is close to it's theoretical probability.</u>
- Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
A similar problem is given at brainly.com/question/24233657
10 times 11% is 11 dollars, so 11 times 10 equals 110. Then 110 plus 100 equals 210. So you'd have $210 after ten years with 11 percent interest.
One function you would be trying to minimize is
<span>f(x, y, z) = d² = (x - 4)² + y² + (z + 5)² </span>
<span>Your values for x, y, z, and λ would be correct, but </span>
<span>d² = (20/3 - 4)² + (8/3)² + (-7/3 + 5)² </span>
<span>d² = (8/3)² + (8/3)² + (8/3)² </span>
<span>d² = 64/3 </span>
<span>d = 8/sqrt(3) = 8sqrt(3)/3</span>