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charle [14.2K]
3 years ago
6

How ti find absolute value

Mathematics
1 answer:
andreyandreev [35.5K]3 years ago
4 0
Absolute value describes how far away a number is from 0

The absolute value of a number is always positive even if you are looking at the absolute value of a negative number.

Examples
The absolute value of 6 = 6
The absolute value of -6 = 6
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Michelle bought five packs of crayons for 13.75. what is the cost of a pack ,in dollars, if all the packs cost the same​
Schach [20]

Answer:

2.75

Step-by-step explanation:

Divide 13.75 by five.

5 0
3 years ago
The ratio of tom’s age to Mary’s is 3:4.If Tom is 15 how old is Mary
AnnZ [28]
Hey there!

Tom's age to Mary's is 3:4; an equivalent ratio is 15:x (x symbolizes Mary's age).

To solve for this, we need to divide our proportions. By that, I mean divide Tom's older age by his younger age. If we do so, we should get a scale factor that we can multiply Mary's younger age by.

15 / 3 = 5

This means that the scale factor of the ages is 5.

x / 4 = 5 (Solving for Mary's unknown age.)

To solve for x, multiply both sides by 4.

x/4 * 4 = x
5 * 4 = 20

x = 20

Mary's age is 20.

I hope this helps!
3 0
3 years ago
Isotope mass (amu) abundance (%) 1 203.97304 1.390 2 205.97447 24.11 3 206.97590 22.09 4 207.97665 52.41 find the atomic mass of
Nata [24]
Answer:
average atomic mass = 207.2172085 amu

Explanation:
To get the average atomic mass of an element using the abundance of its isotopes, all you have to do is multiply each isotope by its percentage of abundance and then sum up all the products.

For the question, we have:
203.97304 amu has an abundance of <span>1.390% (0.0139)
</span>205.97447 amu has an abundance of 24.11% (0.2411)
206.97590 amu has an abundance of 22.09% (0.2209)
207.97665 amu has an abundance of 52.41 % (0.5241)

The average atomic mass can be calculated as follows:
average atomic mass = 203.97304(0.0139) + 205.97447(0.2411)
                                     + 206.97590(0.2209) + 207.97665(0.5241)
average atomic mass = 207.2172085 amu

Hope this helps :)
7 0
3 years ago
The Copy Shop has made 20 copies of a document for you. Since the defective rate is 0.1, you think there may be some defective c
Pepsi [2]

Answer:

Binomial

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

Step-by-step explanation:

For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem

Of the 20 copies, 2 are defective, so p = \frac{2}{20} = 0.1.

What is the probability that you will encounter neither of the defective copies among the 10 you examine?

This is P(X = 0) when n = 10.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.1)^{0}.(0.9)^{10} = 0.3487

There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.

8 0
3 years ago
Need help with this!!
Taya2010 [7]

Answer:

The answer is B..... The corresponding is the identical number between all

The is 7 in each...

8 0
3 years ago
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