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The terms in which value of x when substituted leaves final value of p(x) = "0".
Here, x - 2 is factor. So value of x is 2.
Substituting value of x we get,
p(x) = x3 - 3x + 5a
p(2) = 2*3 - 3(2) + 5a
0+ 8-6 + 5a
-2 = 5a
a= -0.4
Plz mark me as brainliest
First, do the distributive property: 4x-5=4x+2
This answer has no real solution. The term is no real numbers.
Um there needs to be another equation
Answer:
14 flats
5 plants
Step-by-step explanation:
First you would do 89/6 but since that doesn’t divide nicely you can do 90/6 to get 15 then subtract 1 since the original number was 89 and you would get 14
The 14 times 6 would get you 84
Then subtract 84 from 89 and you get 5 plants left over ^^