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Jet001 [13]
3 years ago
6

Explain the process for finding the product of two integers

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0
Rule 1: The product<span> of a positive </span>integer<span> and a negative </span>integer<span> is a negative </span>integer<span>. Rule 2: The </span>product of two<span> negative </span>integers<span> or </span>two<span> positive </span>integers<span> is a positive </span><span>integer</span>
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Solve for x in the equation x2 - 8x+41 - 0
Liula [17]

Answer:

x= 4+5i

Step-by-step explanation:

7 0
3 years ago
What percent of 150 is 162
Novay_Z [31]
To find a percentage of a number, you divide by that number.
So to find what percent of 150 162 is, you divide 162 by 150
162 ÷ 150 = 1.08
Now, to find the percentage, we take the decimal and move the point two places to the right.
1.08 = 108%
162 is 108% of 150.
5 0
3 years ago
The three angle measures in a triangle are congruent. The angles are equiangular! What is the measurement of one of the angles?
gregori [183]

Answer:

60 degrees per angle.

Step-by-step explanation: a triangle has a total of 180 degrees, and the number of sides determine the number of angles it has. in this case, it's an equilateral triangle. 180/3 = 60. all triangles have 3 sides if you didn't know that ;)

4 0
2 years ago
The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75 at
Aleksandr-060686 [28]

A.)y=1.25x+12.5

B.)ridecost+admission=total

if x=number of tickets and y is total and cost per ride is 1.25,

1.25x+admission=y

when we solve

when x=25, y=43.75

Hope This Helps!!!

-Austint1414

5 0
3 years ago
Read 2 more answers
Weights of the vegetables in a field are normally distributed. From a sample Carl Cornfield determines the mean weight of a box
pantera1 [17]
To find the z-score for a weight of 196 oz., use

z=\frac{x-\mu}{\sigma}=\frac{196-180}{8}=\frac{16}{8}=2

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2.  Carl is wondering about the percentage of boxes with weights ABOVE z = 2.  The total area under the normal curve is 1, so subtract .9772 from 1.0000.

1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.

7 0
3 years ago
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