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3 years ago

PLEASE HELP ME! THANK YOU! :)

1 answer:

4 0

All we need to do is to divide August and September rainfall measurements into two equal halves and then substract 0.6 from one of them and add 0.6 to the other one.

6.2 ÷ 2 = 3.1
3.1 - 0.6 = 2.5
3.1 + 0.6 = 3.7

It's said that in August there was 0.6 inch more rainfall, so the bigger value (3.7 inches) is for August and the smaller value (2.5 inches) is for September.

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Esther pays $355 per month for 5 years for a car. She made a down payment of $2,500. If the loan costs 7.1% per year compounded

oksano4ka [1.4K]

The cash price of the car includes the amount of the loan plus the amount of the down payment
Cash price=the loan of the car+down payment

First find the amount of the loan by using the formula of the present value of an annuity ordinary which is
Pv=pmt [(1-(1+r/k)^(-kn))÷(r/k)]
Pv the amount of the loan ?
PMT payment per month 355
R interest rate 0.071
K compounded monthly 12
N time 5years
Pv=355×((1−(1+0.071÷12)^(−12
×5))÷(0.071÷12))
=17,885.56

Cash price=17,885.56+2,500
=20,385.56....answer

5 0

3 years ago

Samantha has chocolate bars and lollipops in the the ratio 4:5. If she has 12 chocolate bars,how many lollipops does she have?

labwork [276]

4 • 3 = 12
5 • 3 = 15
she has 15 lollipops

8 0

3 years ago

A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic

Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are defective?

Solution:

Let the random variable X represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = p = 0.03.

A random sample of n = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable X thus follows a Binomial distribution with parameters n = 10 and p = 0.03.

The probability mass function of X is:

$P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...$

Compute the probability that none of the LED light bulbs are defective as follows:

$P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}$

$=1\times 1\times 0.737424\\=0.737424\\\approx 0.7374$

Thus, the probability that none of the LED light bulbs are defective is 0.7374.

6 0

3 years ago

Please help i need it

PilotLPTM [1.2K]

Whats your question?

4 0

3 years ago

A Lake Tahoe Community College instructor is interested in the mean number of days Lake Tahoe Community College math students ar

Ipatiy [6.2K]

Answer:

She used the simple random sampling technique because there was no condition attached to the samples she took.

Step-by-step explanation:

we have basically four types of sampling

1.Simple random sampling.

2.Systematic sampling.

3.Stratified sampling.

4.Cluster sampling.

simple Random sampling: is a sampling technique where every item in the population has an even chance and likelihood of being selected in the sample.

6 0

3 years ago