<h2>
Greetings!</h2>
Answer:
x = 67.5
Step-by-step explanation:
Because AB and NP lines are parrallel, we can find out the scale factor by dividing size MA by MN.
This works because you find out what the MA size has to be multiplied to to get to MN, which will also work in reverse to find angle MB from MP.
71.5 - 22 = MA = 49.5
71.5 ÷ 49.5 = 
So to get to line MP length, line MB had to be multiplied by to get 97.5
The reverse of this is dividing 97.5 by :
97.5 ÷ 
= 67.5
So x = 67.5
<h2>Hope this helps!</h2>
Answer:x=31.4919
Step-by-step explanation:
Step1:isolate a square root on the left hand side√x+3=√2x-1-2
Step2:eliminate the radicals on the left hand side
Raise both sides to the second power
√x+3)^2=(√2x-1-2)^2
After squaring
x+3=2x-1+4-4-4√2x-1
Step3:get the remaining radicals by itself
x+3=2x-1+4-4√2x-1
Isolate radical on the left hand side
4√2x-1=-x-3+2x-1+4
4√2x-1=x
Step4:eliminate the radicals on the left hand side
Raise both side to the second power
(4√2x-1)^2=x^2
After squaring
32x-16=x^2
Step 5:solve the quadratic equation
x^2-32x-16
This equation has two real roots
x1=32+√960/2=31.4919
x2=32-√960/2=0.5081
Step6:check that the first solution is correct
Put in 31.4919 for x
√31.4919+3=√2•31.4919-1-2
√34.492=5.873
x=31.4919
Step7:check that the second solution is correct
√x+3=√2x-1-2
Put in 0.5081 for x
√0.5081+3=√2•0.5081-1-2
√3.508=-1.873
1.873#-1.873
One solution was found
x=31.4919
Answer:
1/2
Solution: plugging in the given information into the formula you get 2/4 which simplifies to 1/2
Answer:
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
Step-by-step explanation:
Sample size, n = 51
p = 0.62
1 - p = 1 - 0.62 = 0.38
n = 515
Confidence level = 90% = Zcritical at 90% = 1.645
Confidence interval = (p ± margin of error)
Margin of Error = Zcritical * sqrt[(p(1-p))/n]
Margin of Error = 1.645 * sqrt[(0.62(0.38))/515]
Margin of Error = 1.645 * 0.0214
Margin of Error = 0.035203
Lower boundary = (0.62 - 0.035203) = 0.584797
Upper boundary = (0.62 + 0.035203) = 0.655203
(0.5848 ; 0.6552)
We are confident that about 58% to 66% of sea foods in the country are Mislabelled.
No, criticism isnt valid and generalization can be made once the assumptions for constructing a confidence interval is met.
