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Nastasia [14]
3 years ago
8

- What is the slope from the points (2, 3) and (-3,-1) *

Mathematics
2 answers:
iragen [17]3 years ago
6 0

We can use the points (2,3) and (-3,-1) to solve.

Slope formula: y2-y1/x2-x1

= -1-3/-3-2

= -4/-5

= 4/5

Best of Luck!

emmainna [20.7K]3 years ago
5 0

Answer:

4/5

Step-by-step explanation:

To find the slope given two points

m = (y2-y1)/(x2-x1)

   = (-1 -3)/(-3 -2)

    =-4/-5

    = 4/5

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Ents
Natali5045456 [20]

Answer:

48 ≥ 4x + 2y

44 ≥ 2x + 2y

    First, we will look at assembling hours.

"The standard model requires 4 hours to assemble [<em>and</em>] the artisan model requires 2 hours to assemble"

    We also know they have 48 hours per day for assembly, x is standard model and y is artisan model.

48 = 4x + 2y

    Lastly, they do not <em>need</em> to make that many, but they <em>can</em> so we will use greater than or equal to.

48 ≥ 4x + 2y

    Now let us look at finishing hours.

"The standard model requires ... 2 hours for finishing touches. The artisan model requires ... 2 hours for finishing touches."

    We also know they have 44 hours per day for assembly, x is standard model and y is artisan model.

44 = 2x + 2y

    Again, they do not <em>need</em> to make that many, but they <em>can</em> so we will use greater than or equal to.

44 ≥ 2x + 2y

5 0
2 years ago
Isaac has had the same 2 credit cards for 10 years. He has a total credit limit of $12,000. He never makes late payments, and hi
Greeley [361]
D. He will have a low credit score.
7 0
3 years ago
-4x-2y=-12 <br>4x+8y=-24​
sweet [91]

Answer:

x = 6

y = -6

Step-by-step explanation:

By adding both equations :-

=》-4x -2y + 4x + 8y = -12 + (-24)

=》-4x + 4x + 8y - 2y = -12 - 24

=》6y = -36

=》y = -36 ÷ 6

=》y = -6

putting the value of y in equation 2

=》4x + 8y = -24

=》4x + (8 × -6) = -24

=》4x - 48= -24

=》4x = 48 - 24

=》x = 24 / 4

=》x = 6

6 0
3 years ago
Read 2 more answers
If 5&lt;2x+3&lt;11, what is the possible range of value of -4x-6
Lady bird [3.3K]

Answer:

-10 > (-4x - 6) > -22

Step-by-step explanation:

Given inequality is 5 < 2x + 3 < 11

Now we will multiply this inequality by (-2) resulting,

5(-2) > (2x + 3)(-2) > 11(-2)

-10 > (-4x - 6) > -22 (Sign of inequality gets reversed when the inequality is multiplied or divided by a negative number)

Therefore, the possible range of (-4x - 6) is between -22 and -10.

4 0
4 years ago
Mathematical induction, prove the following two statements are true
adelina 88 [10]
Prove:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+n\left(\frac12\right)^{n-1}=4-\dfrac{n+2}{2^{n-1}}
____________________________________________

Base Step: For n=1:
n\left(\frac12\right)^{n-1}=1\left(\frac12\right)^{0}=1
and
4-\dfrac{n+2}{2^{n-1}}=4-3=1
--------------------------------------------------------------------------

Induction Hypothesis: Assume true for n=k. Meaning:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}=4-\dfrac{k+2}{2^{k-1}}
assumed to be true.

--------------------------------------------------------------------------

Induction Step: For n=k+1:
1+2\left(\frac12\right)+3\left(\frac12\right)^{2}+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}

by our Induction Hypothesis, we can replace every term in this summation (except the last term) with the right hand side of our assumption.
=4-\dfrac{k+2}{2^{k-1}}+(k+1)\left(\frac12\right)^{k}

From here, think about what you are trying to end up with.
For n=k+1, we WANT the formula to look like this:
1+2\left(\frac12\right)+...+k\left(\frac12\right)^{k-1}+(k+1)\left(\frac12\right)^{k}=4-\dfrac{(k+1)+2}{2^{(k+1)-1}}

That thing on the right hand side is what we're trying to end up with. So we need to do some clever Algebra.

Combine the (k+1) and 1/2, put the 2 in the bottom,
=4-\dfrac{k+2}{2^{k-1}}+\dfrac{(k+1)}{2^{k}}

We want to end up with a 2^k as our final denominator, so our middle term is missing a power of 2. Let's multiply top and bottom by 2,
=4+\dfrac{-2(k+2)}{2^{k}}+\dfrac{(k+1)}{2^{k}}

Distribute the -2 and combine the fractions together,
=4+\dfrac{-2k-4+(k+1)}{2^{k}}

Combine like-terms,
=4+\dfrac{-k-3}{2^{k}}

pull the negative back out,
=4-\dfrac{k+3}{2^{k}}

And ta-da! We've done it!
We can break apart the +3 into +1 and +2,
and the +0 in the bottom can be written as -1 and +1,
=4-\dfrac{(k+1)+2}{2^{(k-1)+1}}
3 0
3 years ago
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