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Nastasia [14]
3 years ago
8

- What is the slope from the points (2, 3) and (-3,-1) *

Mathematics
2 answers:
iragen [17]3 years ago
6 0

We can use the points (2,3) and (-3,-1) to solve.

Slope formula: y2-y1/x2-x1

= -1-3/-3-2

= -4/-5

= 4/5

Best of Luck!

emmainna [20.7K]3 years ago
5 0

Answer:

4/5

Step-by-step explanation:

To find the slope given two points

m = (y2-y1)/(x2-x1)

   = (-1 -3)/(-3 -2)

    =-4/-5

    = 4/5

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Which is an equation of the line with slope -3 and passes through (2,-1)?
Anuta_ua [19.1K]

Answer:

C

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = - 3, so

y = - 3x + c ← is the partial equation

T find c substitute (2, - 1) into the partial equation

- 1 = - 6 + c ⇒ c = - 1 + 6 = 5

y = - 3x + 5 ← in slope- intercept form

Add 3x to both sides

3x + y = 5 ← in standard form → C

7 0
3 years ago
Read 2 more answers
Can someone help me out my grads are bad
Pani-rosa [81]

Answer:

162

Step-by-step explanation:

9 x 6 = 54

18 x 6 = 108

108 + 54 = 162

8 0
2 years ago
What is the value of the number 6 in the total number 4560 thousand
julsineya [31]
The value of 6 is 60, since it is in the tens place. Hope this helps!
3 0
3 years ago
Read 2 more answers
Question:-
Reika [66]

{\huge \underline{{ \fbox \color{red}{A}}{\fbox \color{green}{n}}{\fbox \color{purple}{s}}{\fbox \color{brown}{w}}{\fbox \color{yellow}{e}}{\fbox \color{gray}{r } }}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \bf \red{ \dfrac{1}{2} +  \dfrac{1}{4} =  \dfrac{3}{4}   }

Step by step explanation :-

The only thing you have to do is add the numerator to the denominator, in this case you have to add the first ones from the front, which can be these 2+1/4, which would result in 3/4, and this is called the Commutative Property.

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{  \bf \gray{ \dfrac{1}{2} +  \dfrac{1}{4}  =  \dfrac{1}{4} +  \dfrac{1}{2}   }}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed{ \bf \green{\dfrac{2 + 1}{4}  =  \dfrac{1 + 2}{4} }}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed {\bf \blue{\dfrac{3}{4}  =  \dfrac{3}{4}} }

Answer :- The answer is 3/4

¿What is commutative property?

It is to change different ways in order of the addends the result would be the same.

Example :-

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \boxed {\bf \blue{\dfrac{a}{b} + \dfrac{c}{d}} = {\dfrac{c}{d}  + \dfrac{a}{b}} }

I hope I've helped : )

5 0
2 years ago
Read 2 more answers
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
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